Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A false sum-check claim rarely becomes true

Statement

At any round i{1,,n} of sum-check, condition on a reached past transcript of positive probability for which Ci1Si1. If the next message fails its format or consistency check it is rejected. Otherwise, conditioned also on the prover's fixed message, the probability that the updated claim becomes true is at most min(1,di/F). The same upper bound holds after averaging over a randomized choice of message. Fresh verifier randomness is drawn after the message.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

The current true value is S_{i-1}, the honest message is q_i, and a fresh uniform r_i is drawn only after h_i is fixed (Sum-check with explicit degree bounds).

[F2]

A nonzero polynomial of degree m over an integral domain has at most m distinct roots in that domain (A nonzero polynomial of degree n over an integral domain has at most n distinct roots).

Proof

1.1

Let qi(T) be the true partial sum at the fixed prefix. Its degree is at most di because specialization and addition preserve degree upper bounds, and qi(0)+qi(1)=Si1. Any well-formed consistent hi instead has hi(0)+hi(1)=Ci1Si1, so hiqi is a nonzero formal polynomial of degree at most di. Messages failing these checks reject immediately.

F1givenalgebra
2.1

A field is an integral domain, since ab=0 with a0 implies b=a1ab=0. Apply the root bound to hiqi: it has at most di roots in F. The next scalar is true precisely if hi(ri)=qi(ri), because Si=qi(ri). The fresh ri is uniform even after conditioning on the fixed message, so this probability is at most min(1,di/F).

F1F2step 1.1algebra
3.1

The bound holds for each allowed message, so averaging its conditional probability over any prover randomness preserves it. If di=0, the nonzero difference is constant and the probability is zero; if diF, the cap at one is merely trivial. The argument includes i=n, n=1, characteristic two, and challenges 0,1. A false updated claim need not be detected in this round; only its becoming true is the exceptional event bounded here.

step 2.1algebra

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources