How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
A maximal element annihilator is prime
Statement
Let be a commutative ring, let be a left -module, and let be nonzero. If is maximal among the annihilators of nonzero elements of , then is a prime ideal.
Facts & Assumptions
Given: A commutative ring , a left -module , and a nonzero element such that is maximal among the annihilators of nonzero elements of .
The annihilator of an element is (Annihilators, torsion elements and the torsion subset of a module).
Proof
Put . Since , one has , so is proper. Let and assume . Then . Also because every satisfies . If , then , so by [L1].
The element is nonzero, so maximality of forces . Since , the element lies in . Therefore and imply , so is prime.
Thus is a prime ideal.
Depends on
Used by
Dependency tree · two levels
4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- A. Altman and S. Kleiman, A Term of Commutative Algebra, 13th ed., Lemma (17.12) (standard reference, not scraped)
- J. S. Milne, A Primer of Commutative Algebra, v4.03, §19 (standard reference, not scraped)