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A nonzero module over a Noetherian ring has a maximal element annihilator

Statement

Assume Dependent Choice.

Let R be a Noetherian commutative ring and let M be a nonzero left R-module. Then there exists a nonzero element mM such that AnnR(m) is maximal, under inclusion, among the annihilators of nonzero elements of M.

Facts & Assumptions

Given: Dependent Choice, a Noetherian commutative ring R, and a nonzero left R-module M.

[L2]

For mM, the annihilator is the set AnnR(m)={rR:rm=0} (Annihilators, torsion elements and the torsion subset of a module).

Proof

technique · direct
1.1

For every mM, the set AnnR(m) is an ideal: it contains 0, is closed under subtraction, and aAnnR(m) implies raAnnR(m) for every rR. Because M0, choose m0M with m00. Then Σ={AnnR(m):mM, m0} is a nonempty set of ideals of R.

L2givenchoosealgebra
2.1

By [L1], the nonempty set Σ has a maximal member. Thus some nonzero mM satisfies that AnnR(m) is maximal among the annihilators of nonzero elements of M.

L1step 1.1
3.1

This is exactly the required conclusion.

step 2.1

Depends on

Used by

Dependency tree · two levels

18 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources