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First variation and optimality over nonnegative measures

Statement

Let H be a real Hilbert space, let Ω be the feature domain, and let F(μ)=R(∫ΩΦ dμ)+∫ΩV dμ be finite on a finite nonnegative Borel measure μ, with R differentiable and convex. Define Gμ(u)=dRmμ[Φ(u)]+V(u), where mμ=∫ΩΦ dμ. Then μ minimizes F over all finite nonnegative Borel measures if and only if Gμ(u)≥0 for every u∈Ω and Gμ(u)=0 for μ-almost every u.

Facts & Assumptions

Given: The feature-measure energy, a finite nonnegative measure μ, and a differentiable convex risk R. For the necessity direction assume μ is a minimizer; for sufficiency assume Gμ≥0 everywhere and Gμ=0 μ-almost everywhere.

[F1]

For a finite nonnegative Borel measure μ on Rd, set F(μ)=R(∫ΩΦ(u) dμ(u))+∫ΩV(u) dμ(u) when μ is concentrated on Ω, the Bochner integral exists, and the scalar integral is finite; set F(μ)=+∞ otherwise. Feature-measure energy and its regularity assumptions

[F2]

A bounded linear map commutes with Bochner integration on every measurable set: T(∫Ef dμ)=∫ETf dμ. Bounded linear maps commute with Bochner integration

[F3]

For u∈Ω, the Dirac measure δu is the Borel probability with δu(A)=1 if u∈A and 0 otherwise. The Dirac set function at a point A Dirac set function is a probability measure

Proof

Given: μ,R,Φ,V as in the Statement.

1.1givenF1F3choose

Fix u∈Ω. For t≥0, the measure μ+tδu from [F3] is nonnegative and F(μ+tδu) is finite for sufficiently small t. Its right derivative at t=0 is dRmμ[Φ(u)]+V(u)=Gμ(u). If μ minimizes F, this derivative is nonnegative. Since u was arbitrary, Gμ≥0 everywhere.

1.2givenF1F2algebra

For t in a neighborhood of 0 with 1+t>0, the measure (1+t)μ is admissible. Differentiating F((1+t)μ) at 0 gives dRmμ[mμ]+∫V dμ=∫Gμ dμ by [F2]. A minimum at the interior parameter t=0 forces this derivative to be zero. Since Gμ is nonnegative and integrable, ∫Gμdμ=0 implies Gμ=0 μ-almost everywhere.

2.1givenF1F2algebra∎

For any finite-energy nonnegative ν, convexity of R gives R(mν)≥R(mμ)+dRmμ[mν−mμ]. By [F2], after adding the V terms this is F(ν)−F(μ)≥∫Gμdν−∫Gμdμ≥0, using the assumed nonnegativity and μ-almost-everywhere vanishing of Gμ. Infinite-energy competitors cannot lower F, so μ is a global minimizer.

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