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Bounded linear maps commute with Bochner integration
Statement
Let be Banach spaces, let be bounded and linear, and let be Bochner integrable. Then is Bochner integrable and, for every measurable ,
Facts & Assumptions
A bounded linear operator satisfies for some finite (A bounded linear operator between normed spaces).
A Bochner integral is the norm limit of integrals of an -approximating simple sequence (Bochner-integrable function).
The Banach-valued simple integral is linear and representation-independent (The Banach-valued simple integral is well defined).
Proof
Given: as in the Statement.
Restrict a defining approximation to the measurable set. Choose integrable simple with . Then is an integrable -valued simple function: every nonzero level is a finite union of level sets of .
Prove Bochner integrability after applying . By [L1], . Thus [L2] makes Bochner integrable.
Commute with the defining limit. [L1, L2, L3, step 1.1, step 2.1] For each simple , finite linearity in [L3] gives . Boundedness makes norm-continuous, so taking limits in this equality and using [L2] proves the displayed identity. If , , or , both sides are explicitly zero.
Depends on
Used by
Dependency tree · two levels
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Sources
- Gerald Teschl, Topics in Real and Functional Analysis (standard reference, not scraped)