Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Monotone chebyshev tauberian desmoothing

Statement

Let A:[1,)[0,) be nondecreasing and locally integrable, with A(x)=O(x), and let a0. If 1(A(x)ax)x2dx converges, then A(x)/xa.

Facts & Assumptions

Given: The data and hypotheses of the statement.

[F1]

Cauchy criterion for improper integrals: The integral af converges if and only if, for every ε>0, there is A>a such that Au<vuvf<ε. At a finite right singular endpoint b, replace the condition by bδ<u<v<b; at a finite left endpoint use a<u<v<a+δ; at use u<vA. In each case all displayed proper integrals must exist.

Proof

1.1

Fix λ>1. The Cauchy criterion makes both tail integrals over [x,λx] and [x/λ,x] tend to zero. Monotonicity gives o(1)A(x)x(1λ1)alogλ,o(1)A(x)x(λ1)alogλ. These inequalities hold for sufficiently large x that x/λ1.

F1given
2.1

Therefore lim supA(x)/xaλlogλ/(λ1) and lim infA(x)/xalogλ/(λ1). Let λ1; both constants tend to a. This also works when a=0 (and nonnegativity supplies a zero lower bound). No differentiation of A or continuity at its jumps was used.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

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Sources