Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The printed diameter-bounded activation class is empty

Statement

For each q≥1, the class BAq in the displayed activation-class definition is empty.

Facts & Assumptions

Given: An integer q≥1 and the definition of BAq.

[F1]

Membership in BAq requires, for every compact K⊂Rq, every ε>0, and every C≥diam⁡2(K), a network satisfying both the identity-approximation and global-bound inequalities (Activation classes for neural-operator universality).

Proof

Proof strategy: direct.

1.1givenF1choose

Suppose σ∈BAq. Choose x0∈Rq with x0≠0, set K={x0}, choose C=0, and choose 0<ε<∣x0∣2. Since a singleton has diameter zero, these choices satisfy the quantifiers in [F1].

2.1givenstep 1.1F1contradiction∎

The required network would satisfy ∣f(x)∣2≤0 for every x∈Rq, hence f(x0)=0. It would also satisfy ∣f(x0)−x0∣2≤ε, which becomes ∣x0∣2≤ε, contrary to the choice of ε. Therefore no σ belongs to BAq.

Remark

The source's immediately adjacent assertion that ReLU belongs to this class cannot follow from the printed definition: the contradiction above applies to every activation. The global-output-bound branch of the source's Theorem 11 is therefore vacuous as printed. A change from diameter to a bound involving the location of K would be a different definition and requires owner reconciliation.

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources