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Away from fixed critical neighborhoods, sufficiently small perturbations create no new critical points on a compact manifold
Statement
Let be a compact smooth manifold, let be Morse, and let be pairwise disjoint critical neighbourhoods as in On a compact manifold, a Morse function has finitely many critical points and a uniform Hessian gap on disjoint critical neighborhoods. Then there is such that every smooth function with on has no critical points in .
Facts & Assumptions
Given: A compact smooth manifold , a Morse function , and pairwise disjoint critical neighbourhoods for the critical points of .
A critical point of a smooth function is precisely a zero of its differential (Critical points and critical values of a smooth function).
The neighbourhoods isolate all critical points of (On a compact manifold, a Morse function has finitely many critical points and a uniform Hessian gap on disjoint critical neighborhoods).
On a compact set, the norm of a continuous cotangent vector field attains its minimum.
Proof
By [L1], the compact set contains no critical point of . Hence [F1] gives for every .
By [A1], the continuous function attains a positive minimum on . Put .
If satisfies on , then for every one has . Therefore on , so [F1] shows that has no critical point in .
Since , this says that sufficiently small perturbations create no new critical points outside the chosen critical neighbourhoods.
Depends on
Used by
Dependency tree · two levels
8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Shintaro Fushida-Hardy, Morse theory (standard reference, not scraped)
- Marco Gualtieri, Topology I: Smooth Manifolds, Part 10 (standard reference, not scraped)