Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-09-05
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Away from fixed critical neighborhoods, sufficiently small C1 perturbations create no new critical points on a compact manifold

Statement

Let M be a compact smooth manifold, let f:MR be Morse, and let U1,,Ur be pairwise disjoint critical neighbourhoods as in On a compact manifold, a Morse function has finitely many critical points and a uniform Hessian gap on disjoint critical neighborhoods. Then there is δ>0 such that every smooth function g with dgdfC0<δ on MiUi has no critical points in MiUi.

Facts & Assumptions

Given: A compact smooth manifold M, a Morse function f:MR, and pairwise disjoint critical neighbourhoods U1,,Ur for the critical points of f.

[F1]

A critical point of a smooth function is precisely a zero of its differential (Critical points and critical values of a smooth function).

[A1]

On a compact set, the norm of a continuous cotangent vector field attains its minimum.

Proof

technique · direct
1.1

By [L1], the compact set K:=MiUi contains no critical point of f. Hence [F1] gives dfx0 for every xK.

F1L1given
2.1

By [A1], the continuous function xdfx attains a positive minimum m on K. Put δ:=m/2.

A1step 1.1choose
3.1

If g satisfies dgdfC0<δ on K, then for every xK one has dgxdfxdgxdfx>mδ=δ>0. Therefore dgx0 on K, so [F1] shows that g has no critical point in K.

F1step 2.1algebra
4.1

Since K=MiUi, this says that sufficiently small C1 perturbations create no new critical points outside the chosen critical neighbourhoods.

step 3.1

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources