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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
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Fibre-regular hypersurface cuts preserve flatness and produce finite image slices

Statement

Assume the Axiom of Choice. For a flat local homomorphism (A,m)→(B,n) of Noetherian local rings and f∈n, if f acts injectively on B/mB, then f is a nonzero divisor on B and B/fB is A-flat. Consequently, let X be an affine finite-type k-scheme, Y,Z finite-type k-schemes, u:Y→X and v:Y→Z morphisms, and z∈v(Y) a closed point such that v is flat at every point over z. There exists a closed subscheme F⊂X such that u((u−1F)z) is finite and nonempty and u−1F→Z remains flat at all its points over z.

Facts & Assumptions

[F1]

Krull intersection holds for finite modules over Noetherian local rings; vanishing of first Tor with the residue field implies base flatness for a module finite over the target local algebra. (The Krull intersection is the (1−a)-torsion submodule, and it vanishes in the Jacobson-radical case, Local flatness criterion by regular parameters, The long exact Tor sequence in the right-module variable)

[F2]

Noetherian rings have finitely many associated primes, and zero divisors lie in their union. Finite prime avoidance and constructibility of finite-type images hold. (Finite modules over Noetherian rings have finitely many associated primes, A zero divisor is contained in an associated prime, An ideal contained in a finite union of prime ideals lies in one of them, Constructible images for finite-presentation affine maps)

Proof

Given: The schemes, maps, and hypotheses in the statement, and AC.

1.1F1givenalgebra

Flatness identifies mjB/mj+1B with (mj/mj+1)⊗A/m(B/mB), by tensoring the inclusions of the ideals of A. Multiplication by f is injective on every such graded piece, since it is injective on the second factor and the first is a vector space. If fb=0, injectivity first gives b∈mB, then successively b∈mjB for every j. Krull intersection in the local ring B gives b=0. The exact sequence 0→B→fB→B/fB→0 and A-flatness of B identify Tor⁡1A(A/m,B/fB) with the kernel of f on B/mB, which is zero. The finite-over-target criterion [F1] proves that B/fB is A-flat. No finiteness over A is used.

2.1F1F2step 1.1constructchoose

If u(Yz) is already finite, take F=X. Otherwise its image is constructible by applying [F2] on a finite affine cover of Yz, and contains infinitely many closed points: a nonempty locally closed positive-dimensional piece has infinitely many closed points, while a zero-dimensional finite-type scheme has only finitely many points. Here κ(z)/k is finite, so Yz is finite type over k. Choose a closed image point x different from the images of the finitely many associated points of Yz. Write X=Spec⁡C and pi for their image primes. Since the maximal ideal mx is not contained in any pi, prime avoidance supplies h∈mx∖⋃ipi. Thus V(h) meets u(Yz) at x and avoids all associated points after pullback. At every point of the cut over z, its defining element is regular in the fibre local ring, and step 1.1 proves flatness of the cut over Z.

3.1F1F2step 1.1step 2.1algebra∎

Repeat inside the affine closed subscheme V(h) if its fibre image is still infinite, using the new fibre's associated points. Each cut has nonempty fibre and is proper: its defining element avoids the fibre's associated points, so cannot vanish identically on that fibre. Thus the defining ideals in the original Noetherian affine ring strictly increase at every repetition. The ascending chain condition forces termination. The last image is finite and nonempty, and step 1.1 preserves the required flatness at each stage. AC is inherited from the associated-prime, Krull-intersection and local-flatness suppliers.

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