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A nonreal Dirichlet L-function is nonzero at one
Statement
If is a nonreal Dirichlet character, then .
Facts & Assumptions
Given: A nonreal Dirichlet character modulo .
The full product has no zero on the line (The full product of Dirichlet L-functions has no zero on Re s = 1).
The principal Dirichlet -function has a simple pole at (The principal Dirichlet L-function factors through zeta).
Every nonprincipal Dirichlet -function is holomorphic on (Nonprincipal Dirichlet L-functions are holomorphic on Re s greater than 0).
Complex conjugation sends a Dirichlet character to another Dirichlet character , and .
Proof
Suppose . Then [A1] gives as well. Because is nonreal, the characters and are distinct, so these are two different vanishing factors in the full finite product at .
In the full product over all characters, [L2] contributes order at , while step 1.1 contributes at least from each of the distinct factors and . Every remaining nonprincipal factor is holomorphic at by [L3], so it contributes order at least . Hence the total product has order at least at , meaning a zero there. This contradicts [L1]. Therefore .
Depends on
Used by
Dependency tree · two levels
13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Kiran S. Kedlaya, Notes on Analytic Number Theory, Theorem 3.10 (standard reference, not scraped)
- Leonard Tomczak, Analytic Number Theory, Chapter 4 (standard reference, not scraped)