Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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A nonreal Dirichlet L-function is nonzero at one

Statement

If χ is a nonreal Dirichlet character, then L(1,χ)0.

Facts & Assumptions

Given: A nonreal Dirichlet character χ modulo q.

[L1]

The full product ψmodqL(s,ψ) has no zero on the line Res=1 (The full product of Dirichlet L-functions has no zero on Re s = 1).

[L2]

The principal Dirichlet L-function has a simple pole at s=1 (The principal Dirichlet L-function factors through zeta).

[L3]

Every nonprincipal Dirichlet L-function is holomorphic on Res>0 (Nonprincipal Dirichlet L-functions are holomorphic on Re s greater than 0).

[A1]

Complex conjugation sends a Dirichlet character to another Dirichlet character χˉ, and L(1,χˉ)=L(1,χ).

Proof

technique · contradiction
1.1

Suppose L(1,χ)=0. Then [A1] gives L(1,χˉ)=0 as well. Because χ is nonreal, the characters χ and χˉ are distinct, so these are two different vanishing factors in the full finite product at s=1.

A1givenassume-contra
2.1

In the full product over all characters, [L2] contributes order 1 at s=1, while step 1.1 contributes at least +1 from each of the distinct factors L(s,χ) and L(s,χˉ). Every remaining nonprincipal factor is holomorphic at 1 by [L3], so it contributes order at least 0. Hence the total product has order at least +1 at 1, meaning a zero there. This contradicts [L1]. Therefore L(1,χ)0.

L1L2L3step 1.1discharge-contradiction

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