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LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-21
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A state-Lipschitz vector field makes the Picard operator a contraction when Lh<1

Statement

On the invariant curve ball of A bounded vector field makes the Picard operator preserve a sufficiently short closed curve ball, suppose F has state-Lipschitz constant L0. Then

d(Tx,Ty)Lhd(x,y).

In particular, if Lh<1, the Picard operator is a contraction.

Facts & Assumptions

Given: Curves x,y in the invariant ball and a state-Lipschitz constant L.

[L1]

For an integrable vector-valued function on [a,b] with ab, abf2abf2 (For ab and f:[a,b]Rm integrable when a<b, abf2abf2; for a<b, f2 is integrable).

[L2]

On every compact time-state cylinder the state-variable inequality holds with one finite constant L (Local Lipschitz continuity in the state variable, locally uniform in time and parameters).

Proof

technique · direct
1.1

Subtracting the two Picard images and applying [L1] and [L2] gives (Tx)(t)(Ty)(t)2Ltt0d(x,y) for every t in the cylinder.

givenL1L2
2.1

Taking the supremum and using tt0h gives the displayed estimate; if Lh<1 this is a contraction, while L=0 gives contraction constant 0.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

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Sources