Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passaudited 2026-08-11
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The parity of transverse ray crossings with a polygon is locally constant on its complement

Statement

For a polygon P (Polygonal arcs and polygons as non-self-intersecting finite unions of line segments in R2) and x∉P, count the intersections modulo two of any general-position ray supplied by Every point off a polygon admits a ray meeting it transversely in finitely many nonvertex points. This parity is independent of the chosen general-position ray and is constant throughout some open neighbourhood of x in the complement. Consequently it is constant on every region of R2∖P (Regions of the complement of a planar set and their frontiers). The elementary alternation at successive transverse crossings follows the convention of The even and odd index maps and the alternating sequence: strictly increasing e,o with N their disjoint union, and the unique (sk) with s0=1, sσ(k)=−sk, which satisfies ∣sk∣=1, s∘e≡1 and s∘o≡−1.

Facts & Assumptions

Given: A polygon P and a point x∉P.

[L1]

Every point off a polygon admits a ray meeting it transversely in finitely many nonvertex points (Every point off a polygon admits a ray meeting it transversely in finitely many nonvertex points).

Proof

technique · direct
1.1

Fix a general-position ray from x. The finite intersection points have positive distance from every polygon vertex and from every nonincident edge; transversality also supplies a positive angle at each crossing. Taking the minimum of finitely many positive tolerances gives a ball about x in which parallel translated rays retain exactly these crossings.

L1
1.2

Rotate one general-position ray continuously to another, avoiding the finitely many exceptional directions except at isolated parameters. Crossing an edge tangentially creates or destroys two intersections, while passing a polygon vertex transfers the intersection from one incident edge to the other or changes the count by two. Thus the count modulo two never changes, so parity is independent of the chosen ray.

L1
2.1

Steps 1.1 and 1.2 make parity locally constant on the complement. A locally constant map to the discrete set {0,1} is constant on each connected component, hence on each complementary region.

step 1.1step 1.2∎

Depends on

Used by

Dependency tree · two levels

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Sources