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A projected unitary block is a contraction

Statement

For a finite system space, an ancilla injection Jax=e0⊗x, and a unitary U on the joint space, the projected block BU=Ja†UJa satisfies ∥BU∥op≤1. Consequently, every exact (α,a,0) block encoding of A satisfies ∥A∥op≤α.

Facts & Assumptions

Given: The compression and exact-block conventions of Finite block encoding, a unitary U, and the finite-dimensional operator norm.

[F1]

Finite block encoding: BU=Ja†UJa, with Ja the isometric inclusion of the all-zero ancilla subspace; in the exact case BU=A^/α, where A^=EoutAEin† and ∥A^∥op=∥A∥op by its Proof, step 3.1.

[F2]

The operator norm is zero on the zero domain and otherwise is max_{||v||=1} ||Tv||: the operator norm is the maximum of ∥Tx∥ over unit vectors, and the zero-domain norm is zero.

Proof

1.1givenF1F2F3algebra

The zero-ancilla coordinate projection Ja† has norm at most one: it discards all coordinates orthogonal to e0⊗Cd, so the squared length of the retained coordinates is at most the squared length of the full vector. Hence for each unit x, ∥BUx∥=∥Ja†UJax∥≤∥UJax∥=∥Jax∥=1, using [F3] and the isometry of Ja from [F1]. Taking the maximum gives ∥BU∥op≤1; the zero-dimensional case follows from [F2].

2.1step 1.1F1F2algebra∎

In the exact case [F1] gives A^=αBU and ∥A∥op=∥A^∥op. The unit-vector definition [F2] gives ∥αBU∥op=α∥BU∥op for positive α, hence ∥A∥op=α∥BU∥op≤α.

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