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Trace of a product of Hermitian matrices is real

Statement

For Hermitian matrices A,B∈Cn×n, n≥0, the trace tr⁡(AB) is real.

Facts & Assumptions

Given: A∗=A and B∗=B in an orthonormal coordinate basis; trace is the diagonal sum, including the empty sum when n=0.

[F2]

In orthonormal bases, the matrix of the adjoint is the conjugate transpose of the matrix: the matrix of an adjoint in orthonormal bases is the conjugate transpose.

[F4]

For A∈Mm×n(F) and B∈Mn×m(F), tr⁡(AB)=tr⁡(BA): for compatible rectangular matrices, tr⁡(UV)=tr⁡(VU).

[F5]

The trace tr⁡(A) as the sum of the diagonal entries: trace is the sum of the diagonal entries, and the empty diagonal sum is zero.

Proof

technique · direct
1.1givenF2F5algebra

Conjugating the diagonal sum in [F5] entry by entry and using [F2] gives tr⁡(AB)‾=tr⁡((AB)∗). For n=0, both sides are the empty sum 0.

2.1givenF1F3F4step 1.1algebra∎

By [F1] and [F3], (AB)∗=B∗A∗=BA. Then [F4] gives tr⁡(BA)=tr⁡(AB), so step 1.1 says tr⁡(AB) equals its conjugate and is real.

Depends on

Used by

Dependency tree · two levels

17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources