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A cyclic group of order n has exactly n additive characters
Statement
Write additively, so denotes the sum of copies of and . If has order , then its set of additive characters has cardinality . Each character is uniquely determined by , and the possible values are exactly the distinct complex th roots of unity. For each such root , the corresponding character is for every .
Facts & Assumptions
Given: A cyclic group of finite order .
An additive character is a group homomorphism and sends to (Additive characters of a finite abelian group); a group homomorphism preserves integer powers, so (A group homomorphism automatically satisfies and , and for every ; for monoid homomorphisms preservation of the identity must be assumed).
The finite-order case of the cyclic classification identifies with by the map ; hence every element is , and exactly when divides (Every cyclic group is isomorphic to or to for its finite order ).
For , the complex th roots of unity are exactly distinct values (The -th roots of a complex number and the distinct roots of unity for every ).
The notation is the set of additive characters of (Dual group of a finite abelian group).
Integer powers in a group satisfy and (Exponent laws in a group: and for all , and when and commute).
Proof
If as defined in [F4], then by [F1] and the given relation , so evaluation at maps this character set into the set in [F3]. Every element is by [F2], and [F1] gives ; thus evaluation at is injective.
Conversely, for each th root of unity , define for . If , [F2] gives for some integer , so by [F3, F5]; hence the value is well defined. Also by [F5], so is an additive character in [F4], and .
Steps 1.1 and 1.2 make evaluation at a bijection from the character set [F4] to the distinct roots in [F3]. This also covers : the quotient is trivial and the sole root is . Therefore .
Depends on
- Dual group of a finite abelian group
- Additive characters of a finite abelian group
- A group homomorphism automatically satisfies $f(e) = e'$ and $f(g^{-1}) = f(g)^{-1}$, and $f(g^{n}) = f(g)^{n}$ for every $n \in \mathbb{Z}$; for monoid homomorphisms preservation of the identity must be assumed
- Exponent laws in a group: $g^{m+n} = g^{m}g^{n}$ and $(g^{m})^{n} = g^{mn}$ for all $m, n \in \mathbb{Z}$, and $(gh)^{n} = g^{n}h^{n}$ **when $g$ and $h$ commute**
- Every cyclic group is isomorphic to $(\mathbb Z,+)$ or to $(\mathbb Z/n,+)$ for its finite order $n\ge1$
- The $n$-th roots of a complex number and the $n$ distinct roots of unity for every $n\ge1$
Used by
- One finite abelian hidden-subgroup Fourier sample Algorithm
- Finite abelian hidden-subgroup promise and output encoding Definition
- Common-kernel subgroup recovery in a product of cyclic groups Example
- Finite abelian Fourier and convolution examples Example
- Fourier sampling for a cyclic subgroup Example
- Fourier annihilator equation for cyclic discrete logarithm Lemma
- A finite abelian group and its character dual have equal order Theorem
- Dual-index character orthogonality Theorem
- Finite abelian group is canonically isomorphic to its double dual Theorem
- Finite abelian hidden-subgroup query and circuit costs Theorem
Dependency tree · two levels
41 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Ronald de Wolf, Quantum Computing: Lecture Notes, version 6 (standard reference, not scraped)
- Andrew M. Childs, Lecture Notes on Quantum Algorithms (standard reference, not scraped)
- John Preskill, Quantum Information, Chapter 6: Quantum Algorithms (standard reference, not scraped)