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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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The Knill–Laflamme coefficient matrix is positive

Statement

Let HL,HP,HO be finite-dimensional complex inner-product spaces, V:HL→HP an isometric encoding of nonzero logical space, and P=VV∗. For a finite family of linear error operators E1,…,Em:HP→HO, suppose scalars Cab satisfy PEa∗EbP=CabP for all a,b. Then the matrix C=(Cab) is Hermitian positive semidefinite.

Facts & Assumptions

Given: The finite-dimensional encoding and error family in the Statement, and the displayed Knill–Laflamme scalar-compression identities.

[F2]

An isometric quantum encoding gives an orthogonal code projector: V∗V=IHL, P∗=P=P2, and PV=V.

[F3]

Real and complex inner product spaces, with the inner product linear in the first argument: the complex inner product is linear in its first argument and conjugate-linear in its second.

Proof

1.1givenF2F4choosealgebra

By [F2], PV=V, V∗P=V∗ and V∗V=IHL. Multiplying PEa∗EbP=CabP by V∗ and V therefore gives V∗Ea∗EbV=CabIHL. Choose a unit vector ψ∈HL, possible because HL≠{0}. The adjoint identity [F4] yields Cab=⟨Ea∗EbVψ,Vψ⟩=⟨EbVψ,EaVψ⟩.

2.1step 1.1F3algebra∎

For any z=(z1,…,zm)∈Cm, the first-argument linearity and conjugate symmetry in [F3] give z∗Cz=∑a,bza‾zb⟨EbVψ,EaVψ⟩=∥∑bzbEbVψ∥2≥0. Also Cba=Cab‾, so C is Hermitian. The nonnegative quadratic form is exactly positive semidefiniteness.

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