Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The quotient seminorm is independent of the chosen coset representative

Statement

Let X be a normed space and let MX. If x+M=x+M in X/M, then

infmMx+m=infmMx+m.

Therefore the quotient seminorm of The quotient seminorm (|x+M|{X/M}=\inf{m\in M}|x+m|=\operatorname{dist}(x,M)) is well defined.

Facts & Assumptions

Given: A normed space X, a linear subspace MX, and representatives x,xX with x+M=x+M.

[L1]

The quotient seminorm is defined by x+MX/M:=infmMx+m (The quotient seminorm (|x+M|{X/M}=\inf{m\in M}|x+m|=\operatorname{dist}(x,M))).

[L2]

Two cosets are equal exactly when their representatives differ by an element of M (Coset equality, well-defined quotient operations, and the canonical projection with kernel W).

Proof

technique · direct
1.1

By [L2], there is m0M with x=x+m0. For every mM, x+m=x+(m0+m), and m0+m still lies in M. Thus {x+m:mM}{x+n:nM}.

L2
2.1

The same argument with the roles of x and x reversed gives the reverse inclusion, so the two sets of admissible norms are equal. Their infima are therefore equal, which is exactly the claim of [L1].

step 1.1L1L2

Depends on

Used by

Cited to discharge well-definedness by The quotient seminorm (‖x+M‖_X/M=inf_m∈ M‖x+m‖=dist(x,M)).

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources