Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-13
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The expected number of cycles of length at most in G(n,p)

Statement

Let X be the number of cycles of lengths 3 through in G(n,p). Then E[X]=r=3nr2rprr=3nrpr2r. If <3, both sums are empty and equal zero.

Facts & Assumptions

Given: Naturals n, and p[0,1].

[L1]

G(n,p) has mutually independent Bernoulli edge coordinates (The Erdős-Rényi finite random graph G(n,p)).

[L2]

A cycle is a closed walk of length at least 3 whose vertices, apart from the coinciding endpoints, are distinct (Walks, closed walks, trails, paths and cycles, with length equal to the number of traversed edges), and the girth is the least length of a cycle (Graph distance within a component, eccentricity, diameter and girth, including the acyclic convention).

[L3]

A prescribed set of r present edges has probability pr (A prescribed set of present and absent edges in G(n,p) has product probability).

[L4]

The falling factorial nr is defined by n0=1 and nk+1=nk(nk) (The factorial n! and the falling factorial nk, defined by recursion in N), and for finite sets A=n, B=r the injections BA number nr (The number of injections from a k-element set into an n-element set is nk). An ordered list of r distinct vertices is such an injection, so there are nr of them.

Proof

technique · direct
1.1

An undirected r-cycle is represented by 2r ordered lists of its vertices, one for each starting point and direction. Hence there are nr/(2r) labelled r-cycles.

L2L4algebra
1.2

In G(n,p), each such cycle occurs with probability pr.

L1L3
2.1

Sum its indicator over all cycles and all 3r. By [L5], the expectation is the first displayed sum.

step 1.1step 1.2L5
3.1

Since nrnr, the stated upper bound follows. When <3 the index set is empty. The formula includes p=0,1.

step 2.1algebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 86 results over 21 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources