Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An ϵ-regular pair is ϵ-regular for every ϵϵ with ϵ>0

Statement

Let 0<ϵϵ. If (X,Y) is an ϵ-regular pair, then it is an ϵ-regular pair.

Facts & Assumptions

Given: Reals 0<ϵϵ, disjoint nonempty vertex sets X,Y, and an ϵ-regular pair (X,Y).

[L1]

An ϵ-regular pair requires the density deviation bound for all subsets XX, YY with XϵX and YϵY (ϵ-regular pairs and self-regular vertex sets, Edge counts and densities between nonempty vertex sets).

Proof

technique · direct
1.1

If XϵX and YϵY, then also XϵX and YϵY because ϵϵ.

L1algebra
2.1

The ϵ-regularity of (X,Y) therefore gives d(X,Y)d(X,Y)ϵϵ. This is exactly the definition of ϵ-regularity.

step 1.1L1algebra

Depends on

Used by

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources