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The difference of the Weyl vector from its reflections is a sum of positive roots

Statement

Let Φ be the root system with positive system Φ+, simple roots α1,…,αr, Weyl group W and Weyl vector ρ=12∑α∈Φ+α (Finite Weyl root system, lattice and chamber conventions, The Weyl vector rho for a chosen positive system, Root reflections and the Weyl group action). For every w∈W, ρ−wρ=∑α∈Φ+w−1α∈Φ−α, the sum running over the positive roots whose image under w−1 is a negative root. In particular ρ−wρ∈Q+: it is a nonnegative integral combination of the simple roots.

Facts & Assumptions

Given: The finite root-system, positivity, length and lattice conventions of Finite Weyl root system, lattice and chamber conventions, a positive system Φ+ with simple roots αi, the Weyl group W, the Weyl vector ρ, and an element w∈W.

[F3]

The reflection sα acts by sα(λ)=λ−⟨λ,α∨⟩α and the Weyl vector is ρ=12∑α∈Φ+α (Root reflections and the Weyl group action, The Weyl vector rho for a chosen positive system).

[F4]

Every positive root is a nonnegative integral combination of the simple roots, so Φ+⊆Q+ (Simple roots form a signed integral basis, Finite Weyl root system, lattice and chamber conventions).

Proof

technique · direct
1.1F3givenalgebra

Put S={α∈Φ+:w−1α∈Φ−}. Since w permutes the roots, wΦ+ contains α for each α∈Φ+∖S and −α for each α∈S, each exactly once: these assertions are respectively equivalent to w−1α>0 and w−1(−α)>0. Therefore 2wρ=∑α∈Φ+∖Sα−∑α∈Sα.

2.1F3F4step 1.1algebra∎

Subtracting the expression in step 1.1 from 2ρ=∑α∈Φ+α gives ρ−wρ=∑α∈Sα. Every summand belongs to Q+ by [F4], proving the claimed cone inclusion. For w=1 or the empty root system the sum is empty and the same calculation gives zero.

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