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The sign of the Weyl length is multiplicative

Statement

Let W be the Weyl group of the root system Φ with its real span E=span⁡RΦ and length function ℓ (Finite Weyl root system, lattice and chamber conventions, Root reflections and the Weyl group action). Then (−1)ℓ(uv)=(−1)ℓ(u)(−1)ℓ(v)(u,v∈W), so that w↦(−1)ℓ(w) is a group homomorphism W→{±1}, and this homomorphism is the determinant of the action of W on E: (−1)ℓ(w)=det⁡(w) for every w∈W. In particular (−1)ℓ(w−1)=(−1)ℓ(w).

Facts & Assumptions

Given: The finite root system Φ spanning the real vector space E of dimension n with its positive definite form, the Weyl group W generated by the root reflections sα, its simple reflections si and the length function ℓ, and elements u,v,w∈W.

[F1]

For each root α the reflection sα(λ)=λ−⟨λ,α∨⟩α fixes α⊥ pointwise and sends α to −α; in particular E=Rα⊕α⊥ and α∧e2∧⋯∧en is a nonzero element of ΛnE for a basis e2,…,en of α⊥ (Root reflections and the Weyl group action, Finite Weyl root system, lattice and chamber conventions).

[F2]

If T:V→V is an endomorphism of an n-dimensional vector space, then ΛnT=det⁡(T)⋅id⁡ΛnV on the one-dimensional space ΛnV; and det⁡(S∘T)=det⁡(S)det⁡(T) for endomorphisms S,T (On ΛnV, the induced map ΛnT is multiplication by det⁡T, Determinant multiplicativity follows from the top exterior power).

[F3]

The simple reflections generate W and ℓ(w) is the least number of simple reflections in an expression for w; every simple reflection si is a root reflection and ℓ(si)=1; all of this includes the case Φ=∅, where E=0 and W={1} (Finite Weyl positive roots and simple reflections, Finite Weyl root system, lattice and chamber conventions, Weyl length equals inversion number).

Proof

technique · direct
1.1F1F2algebra

If E=0, then W={1} and both the length sign and the determinant of its identity are 1, so all assertions hold. Assume dim⁡E≥1. For every root α one has det⁡(sα)=−1: choosing the basis (α,e2,…,en) of E with e2,…,en a basis of α⊥, [F1] gives sα(α)=−α and sα(ei)=ei, so Λnsα(α∧e2∧⋯∧en)=(−α)∧e2∧⋯∧en=−(α∧e2∧⋯∧en), and since this wedge is a basis of the one-dimensional space ΛnE, [F2] forces det⁡(sα)=−1.

2.1F2F3step 1.1algebra

Every w∈W is a product of simple reflections by [F3]; if w=si1⋯sik is any such expression, then repeated use of [F2] together with step 1.1 gives det⁡(w)=∏j=1kdet⁡(sij)=(−1)k, so det⁡(w) agrees with (−1)k for every expression of w; choosing an expression of minimal length k=ℓ(w), which exists by [F3], gives det⁡(w)=(−1)ℓ(w).

3.1F2step 2.1algebra∎

For u,v∈W the multiplicativity in [F2] and step 2.1 give (−1)ℓ(uv)=det⁡(uv)=det⁡(u)det⁡(v)=(−1)ℓ(u)(−1)ℓ(v), so w↦(−1)ℓ(w) is a homomorphism W→{±1} agreeing with the determinant; applying it to w−1 and using det⁡(w)−1=det⁡(w)∈{±1} gives (−1)ℓ(w−1)=det⁡(w−1)=det⁡(w)=(−1)ℓ(w).

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