Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Monotonicity of the bumping route and standardness of the output

Statement

Let T be a standard tableau with distinct real entries and let x∉T be a real number, with the notation of Row insertion and the bumping route for T←x. Then:

  1. the bumped letters strictly increase, x=x1<x2<⋯<xs, and the route positions weakly decrease, r1≥r2≥⋯≥rs≥1;
  2. the new box b=(s,rs) is an addable node of [shape⁡(T)], and T←x is a standard tableau of shape shape⁡(T)+b whose entries are exactly the entries of T together with x.

Facts & Assumptions

Given: A standard tableau T with distinct real entries and a real number x that is not an entry of T.

[L1]

At row i of T←x: if row i is nonempty and some entry exceeds xi, then ri is the position of the leftmost such entry yi, the entry is replaced by xi and xi+1:=yi; otherwise xi is appended at the right end of row i, at position λi+1, and the route stops (Row insertion and the bumping route).

[L2]

For the distinct real alphabets of Row insertion and the bumping route, a standard tableau is an injective filling with strictly increasing rows and columns; its rank relabelling gives a standard tableau in the published alphabet {1,…,n}, and (i,j)∈[λ] with (i+1,j)∈[λ] implies T(i,j)<T(i+1,j) (Tableaux and standard tableaux, Partitions, English diagrams, and conjugation).

[L3]

A node (i,λi+1) is addable for λ if and only if i=1 or λi−1>λi; and [λ]∪{(i,λi+1)} is then the diagram of a partition (Removable and addable nodes).

Proof

technique · direct
1.1L1given

The bumped letters increase: when the route replaces at row i, the new carried letter is xi+1=yi>xi by the leftmost-greater choice of ri; hence x=x1<x2<⋯<xs.

1.2L1L2

The positions weakly decrease: supposing the route continues from row i to row i+1 with ri defined, if row i+1 has length λi+1≥ri, then the entry of T at (i+1,ri) lies below the old entry yi=xi+1 of (i,ri), so it exceeds xi+1; the leftmost entry of row i+1 exceeding xi+1 is therefore at a position ri+1≤ri. If instead λi+1<ri, the next step either bumps at ri+1≤λi+1 or appends at ri+1=λi+1+1; both give ri+1≤ri.

2.1step 1.2L1

The route terminates at a well-defined row s: the positions are positive integers with r1≤λ1+1, they weakly decrease along the visited rows, and after the last nonempty row the next row is empty and the letter is appended, so only finitely many rows are visited and the appended new box is b=(s,rs) with rs=λs+1.

3.1step 1.2step 2.1L3

The new box is addable: if s=1 then b=(1,λ1+1) is addable by [L3]; if s>1, the route reached row s after replacing at row s−1, so rs−1≤λs−1 and rs=λs+1≤rs−1 by step 1.2, whence λs<λs−1 and b is addable by [L3].

3.2step 2.1L1

The entries of the output are exactly the entries of T together with x: each row visit writes the carried letter xi into a box of row i and removes the entry yi=xi+1 from it, and the final visit appends xs into the new box without removing anything; thus the multiset of entries changes from that of T by adding x1=x and deleting nothing, and the shape grows by the single box b.

4.1step 1.1step 1.2step 3.1L1L2

The output is standard: the replaced entries keep strictly increasing rows because xi is placed at the leftmost position whose old entry exceeded it, so its left neighbour is <xi and its right neighbour is larger than the displaced entry and hence >xi, and an appended letter exceeds every entry of its row; columns remain strictly increasing because at each replaced box (i,ri) the entry above is either a previously placed bumped letter xi−1<xi or an unchanged entry lying left of the old entry xi in row i−1, hence smaller than xi, and the entry below is either the newly placed xi+1>xi (when ri+1=ri) or the unchanged entry at (i+1,ri), which exceeds the old entry yi=xi+1 and hence xi (when ri+1<ri), while the appended box (s,λs+1) lies below either a placed xs−1<xs or an unchanged entry left of the old entry xs of (s−1,rs−1); all other boxes are unchanged.

5.1step 3.1step 3.2step 4.1∎

The output is a standard tableau of shape shape⁡(T)+b with entries those of T plus x, as asserted.

Depends on

Used by

Dependency tree · two levels

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Sources