Alphabeta Math
LemmaStatement: Literature-sourcedProof: Literature-sourcedPipeline-generatedjudge pass (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The recording tableau is standard

Statement

Let w=(w1,…,wN) be a word of pairwise distinct real numbers and define P0:=∅ and Pk:=Pk−1←wk for 1≤k≤N (Row insertion and the bumping route). Let Qk be the filling of [shape⁡(Pk)] that carries the label k in the box added at step k and the label j in the box added at step j for j<k; the boxes added at the successive steps are distinct addable nodes by Monotonicity of the bumping route and standardness of the output. Then every Qk is a standard tableau with entries 1,…,k of the same shape as Pk; in particular QN is a standard tableau of size N.

Facts & Assumptions

Given: A word w=(w1,…,wN) of pairwise distinct real numbers and the tableaux P0,…,PN, with the box bk added at step k and the fillings Qk.

[L1]

Pk is standard and bk is an addable node of [shape⁡(Pk−1)]; consequently [shape⁡(Pk)]=[shape⁡(Pk−1)]∪{bk}, the node bk is the end of its row and of its column of [shape⁡(Pk)], and the shape grows by exactly one box at each step (Monotonicity of the bumping route and standardness of the output).

[L2]

A standard tableau is a bijection from its diagram to an initial segment {1,…,m} with strictly increasing rows and columns (Tableaux and standard tableaux).

[L3]

A node (i,λi+1) addable for λ satisfies i=1 or λi−1>λi, so after insertion it has no box to its right and, by weak decrease of the rows, no box below it (Removable and addable nodes, Partitions, English diagrams, and conjugation).

Proof

technique · induction
1.1baseL2given

Base: Q0 is the empty filling of the empty shape, which is standard with entry set ∅, and shape⁡(Q0)=shape⁡(P0).

1.2ihgiven

Induction hypothesis: suppose Qk−1 is a standard tableau with entries 1,…,k−1 of shape shape⁡(Pk−1).

2.1step 1.2L1L3

The box bk is the end of its row and of its column in [shape⁡(Pk)] by [L1], so in Qk the new label k has no right and no lower neighbour; its left neighbour and its upper neighbour, if present, carry labels <k, and every comparison not involving bk is one already present in Qk−1. Hence, with k the largest label, rows and columns of Qk are strictly increasing.

3.1step 1.2step 2.1L1

The filling Qk is a bijection from [shape⁡(Pk)] onto {1,…,k}: Qk−1 is a bijection onto {1,…,k−1} by the induction hypothesis, the shapes differ by the single node bk, and Qk agrees with Qk−1 off bk and carries label k on it.

4.1step 1.1step 1.2step 2.1step 3.1discharge-induction∎

By steps 2.1 and 3.1 and the induction hypothesis, Qk is a standard tableau with entries 1,…,k of shape shape⁡(Pk), for every k≤N, and induction over k=0,…,N proves the assertion; in particular QN is standard of size N.

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources