Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The printed all-scale probability cell-mass bound is inconsistent

Statement

Let X be a nonempty measurable space, let d≥1, let c>0, and let μ be a probability measure on X. There is no family of finite measurable partitions Pε of X, one for every ε>0, for which every cell E∈Pε satisfies μ(E)≥cεd.

Facts & Assumptions

Given: A probability measure μ on nonempty X, an integer d≥1, and a constant c>0.

[F1]

A probability measure satisfies μ(X)=1 (Probability measures and probability spaces).

[F2]

If E⊆X is measurable, then μ(E)≤μ(X) (Measures are monotone).

Proof

technique · choose one scale at which the asserted lower bound exceeds total mass
1.1givenF1F2choose

Choose ε>c−1/d. Since X is nonempty, any partition of X has at least one cell E. The set E is measurable and E⊆X, so [F1] and [F2] give μ(E)≤1.

2.1givenstep 1.1algebracontradiction∎

The asserted lower bound gives μ(E)≥cεd>1, contradicting step 1.1. Hence no such all-scale family of partitions exists.

Depends on

Used by

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources