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Under sigma-finiteness, every Carathéodory measurable set differs from a generated measurable hull by a null set
Statement
Assume countable choice. If is sigma-finite, is its induced outer measure, and is Carathéodory measurable, then there is with and .
Facts & Assumptions
Given: Countable choice, a sigma-finite premeasure , a covering sequence of finite premeasure, and a Carathéodory measurable set .
A premeasure on an algebra vanishes at the empty set and is countably additive whenever a disjoint sequence in has its union in . (Premeasures on algebras of sets)
Assuming countable choice, an outer measure induced by a premeasure is regular, and every set has a measurable hull in . (Assuming countable choice, a premeasure-induced outer measure is regular with generated measurable hulls)
Assuming countable choice, the induced outer measure restricts to a complete measure on its Carathéodory sigma-algebra and to a measure on extending . (Assuming countable choice, a premeasure extends through its induced outer measure)
Proof
Put , so [F1] gives , , and ; using countable choice and [L1], select with and .
Both and are Carathéodory measurable by [L2], and their common measure is finite, so additivity on gives .
The set belongs to and contains because ; moreover is contained in the union of the null excesses from step 2.1, so countable subadditivity gives .
Depends on
- Premeasures on algebras of sets
- Assuming countable choice, a premeasure-induced outer measure is regular with generated measurable hulls
- Assuming countable choice, a premeasure extends through its induced outer measure
- Carathéodory measurable sets
- The sigma-algebra generated by a family of sets
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
Used by
Dependency tree · two levels
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Sources
- G. Folland, Real Analysis, 2nd ed., Exercise 18(c) in Section 1.4 (standard reference, not scraped)
- T. Tao, An Introduction to Measure Theory, Exercise 1.7.9(i) (standard reference, not scraped)