Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Slicing lemma: large subpairs remain regular and their density shifts by at most ϵ

Statement

Let (X,Y) be ϵ-regular, and let XX, YY satisfy XαX and YβY, where α,βϵ>0. Then d(X,Y)d(X,Y)ϵ, and (X,Y) is ϵ-regular for ϵ=max{ϵ/α,ϵ/β,2ϵ}.

Facts & Assumptions

Given: The pair and subsets in the Statement.

[L1]

An ϵ-regular pair has every subpair whose two sides meet the ϵ relative-size thresholds within ϵ of its density (ϵ-regular pairs and self-regular vertex sets).

Proof

technique · direct
1.1

Since XϵX and YϵY, [L1] gives d(X,Y)d(X,Y)ϵ.

givenL1
1.2

Let AX and BY satisfy AϵX and BϵY. Then A(ϵ/α)αX=ϵX and similarly BϵY.

givenalgebra
2.1

By [L1], d(A,B)d(X,Y)ϵ; combining this with step 1.1 yields d(A,B)d(X,Y)2ϵϵ.

step 1.1step 1.2L1algebra
3.1

Since A,B were arbitrary at the ϵ thresholds, (X,Y) is ϵ-regular.

step 2.1L1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 4 results over 4 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources