Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Slicing lemma: large subpairs remain regular and their density shifts by at most ϵ

Statement

Let (X,Y) be ϵ-regular, and let X′⊆X, Y′⊆Y satisfy ∣X′∣≥α∣X∣ and ∣Y′∣≥β∣Y∣, where α,β≥ϵ>0. Then ∣d(X′,Y′)−d(X,Y)∣≤ϵ, and (X′,Y′) is ϵ′-regular for ϵ′=max⁡{ϵ/α,ϵ/β,2ϵ}.

Facts & Assumptions

Given: The pair and subsets in the Statement.

[L1]

An ϵ-regular pair has every subpair whose two sides meet the ϵ relative-size thresholds within ϵ of its density (ϵ-regular pairs and self-regular vertex sets).

Proof

technique · direct
1.1givenL1

Since ∣X′∣≥ϵ∣X∣ and ∣Y′∣≥ϵ∣Y∣, [L1] gives ∣d(X′,Y′)−d(X,Y)∣≤ϵ.

1.2givenalgebra

Let A⊆X′ and B⊆Y′ satisfy ∣A∣≥ϵ′∣X′∣ and ∣B∣≥ϵ′∣Y′∣. Then ∣A∣≥(ϵ/α)α∣X∣=ϵ∣X∣ and similarly ∣B∣≥ϵ∣Y∣.

2.1step 1.1step 1.2L1algebra

By [L1], ∣d(A,B)−d(X,Y)∣≤ϵ; combining this with step 1.1 yields ∣d(A,B)−d(X′,Y′)∣≤2ϵ≤ϵ′.

3.1step 2.1L1∎

Since A,B were arbitrary at the ϵ′ thresholds, (X′,Y′) is ϵ′-regular.

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources