Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-26
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A subset occupying at least a λ fraction of a c-sparse set is (c/λ)-sparse

Statement

Let G be a finite simple graph, let c≥0, let λ>0, and let X′⊆X⊆V(G) be nonempty. If X is c-sparse and ∣X′∣≥λ∣X∣, then X′ is (c/λ)-sparse.

Facts & Assumptions

Given: A finite simple graph G, reals c≥0 and λ>0, and nonempty sets X′⊆X⊆V(G) such that X is c-sparse and ∣X′∣≥λ∣X∣.

Proof

technique · direct
1.1L1

For every x∈X′, the degree of x in G[X′] is at most its degree in G[X].

2.1step 1.1L1algebra

Since X is c-sparse, [L1] gives deg⁡G[X](x)≤c∣X∣; and because ∣X′∣≥λ∣X∣, one has ∣X∣≤∣X′∣/λ. Hence deg⁡G[X′](x)≤(c/λ)∣X′∣ for every x∈X′.

3.1step 2.1L1∎

Applying [L1] again shows that X′ is (c/λ)-sparse.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources