Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A subset occupying at least a λ fraction of a c-sparse set is (c/λ)-sparse

Statement

Let G be a finite simple graph, let c0, let λ>0, and let XXV(G) be nonempty. If X is c-sparse and XλX, then X is (c/λ)-sparse.

Facts & Assumptions

Given: A finite simple graph G, reals c0 and λ>0, and nonempty sets XXV(G) such that X is c-sparse and XλX.

Proof

technique · direct
1.1

For every xX, the degree of x in G[X] is at most its degree in G[X].

L1
2.1

Since X is c-sparse, [L1] gives degG[X](x)cX; and because XλX, one has XX/λ. Hence degG[X](x)(c/λ)X for every xX.

step 1.1L1algebra
3.1

Applying [L1] again shows that X is (c/λ)-sparse.

step 2.1L1

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources