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Spectral form domain and core of a semibounded operator

Statement

Assume the Axiom of Choice. Let A be self-adjoint on a complex Hilbert space H, with AcI meaning Ax,xcx2 for every xD(A), for some real c. Put Q(A):=D((AcI)1/2),qA[x]:=cx2+(AcI)1/2x2(xQ(A)). Then Q(A) and qA do not depend on the choice of the constant cinfσ(A) (the form qA[x]=λdEx is itself unchanged, while the summand (AcI)1/2x2 changes by the constant (cc)x2 when c is replaced by cc), qA[x]=λdEx(λ)=Ax,x for xD(A), the domain D(A) is dense in Q(A) for the norm xQ=(x2+(AcI)1/2x2)1/2, and qA is a closed quadratic form with qA[x]cx2.

Here the square root is the Borel calculus of max(λc,0); the proof shows that E is carried on [c,). A closed semibounded quadratic form means the diagonal of a Hermitian sesquilinear form on a dense linear domain, complete in the displayed shifted form norm. If H={0}, use the unique PVM and operator and the convention inf(empty spectrum)=+infinity.

Facts & Assumptions

[A1]

The spectral theorem gives D(A)={x:λ2dEx<} and A as the coordinate integral on nonzero H. The unbounded integral is closed, has linear domain, squared norm integral, and real-function pairing f(E)x,x=fdEx. Real f gives a self-adjoint operator. The zero-space integral is defined directly. Spectral theorem for unbounded self-adjoint operators (PVM form) The unbounded PVM integral is densely defined, closed and normal Integral of a measurable function against a projection-valued measure

[A2]

Projections multiply by intersection, and Ex(B)=E(B)x2 is a finite measure of mass x2. Consequently EE(J)x(B)=Ex(BJ), using E(B)E(J)=E(BJ) and the norm formula; complementary projections give the analogous complementary restriction. The spectrum of A is the essential range of the coordinate function. Projection valued measure Unbounded Borel functional calculus: domains, products, spectral mapping

[A3]

Scalar dominated convergence applies to the finite measures E_x. Dominated convergence

[A4]

H is complete and its inner product is first-linear. Self-adjoint operators have dense linear domains. The assumed AC directly supplies every choice function required by the PVM, closed-integral and spectral-theorem interfaces. Hilbert space Symmetric, self-adjoint and essentially self-adjoint operators The Axiom of Choice

Proof

technique · direct

Given: AC, self-adjoint A and its lower bound c.

1.1

If H={0}, every domain and form consists of zero, all norms vanish, and every assertion follows directly from the zero-space convention in [A1]. Otherwise obtain E from [A1], under the choice assumption in [A4]. For Jm=[m,c1/m] (empty intervals allowed), a vector v=E(Jm)x belongs to D(A) by [A2] and boundedness of lambda on J_m. If v were nonzero then Av,v=JmλdEv(c1/m)v2, contradicting the lower bound. Thus E(J_m)=0 for all positive integers m. Their union is (,c), whose scalar measures therefore vanish by countable subadditivity. The projection norm formula gives E((-infinity,c))=0. The essential-range description in [A2] implies σ(A)[c,).

A1A2A4given
2.1

Put B=max(λc,0)(E). It is closed and self-adjoint by [A1], and step 1.1 gives D(B)={x:(λc)dEx<} and Bx2=(λc)dEx. Integrals here and below can be restricted to [c,infinity). Since λ(λc)+c there, lambda is absolutely integrable for x in Q(A). Hence qA[x]=cx2+Bx2=λdEx and qA[x]cx2.

A1A2step 1.1
3.1

For any other lower spectral bound c'<=c, λc=(λc)+(cc) on the carrier. Since E_x has finite mass, the two domain integrals are finite simultaneously. Adding the appropriate constant times the mass gives the same q_A, while the square-root squared norm increases by (cc)x2. Two arbitrary admissible lower bounds can be compared in their numerical order, so this proves full independence. Their squared form norms differ by that same multiple of x2, hence are equivalent since each dominates x2.

A2step 2.1
3.2

If x belongs to D(A), then λc1+λ2+c on the carrier, so x belongs to Q(A). By [A1] and step 2.1, qA[x]=λdEx=Ax,x.

A1A2step 2.1
3.3

For x in Q(A), set xn=E([n,n])x, n>=1. By [A2], λ2dExnn2x2, so x_n belongs to D(A). The same restriction identity gives xxnQ2=λ>n(1+λc)dEx0 by dominated convergence, with nonnegative integrable majorant 1+λc on the carrier. This is the asserted form-norm density, with the exact identity zQ2=qA[z]+(1c)z2.

A1A2A3step 2.1
4.1

The form is the diagonal of a(x,y)=cx,y+Bx,By on the linear domain D(B); this is Hermitian and sesquilinear by [A4]. Its domain is dense in H because it contains D(A) by step 3.2. For a Cauchy sequence in the form norm, both x_n and Bx_n are Cauchy in H. Completeness gives limits x and y. Closedness of B implies x in D(B) and Bx=y. Therefore xnxQ2=xnx2+BxnBx20, proving completeness and closedness in the stated sense.

A1A4step 2.1step 3.2
5.1

Steps 2.1 and 3.1 establish the domain, integral identity, lower bound and independence; steps 3.2 and 3.3 give the operator-domain identity and core, and step 4.1 gives the closed quadratic form. Positive integer cutoffs are specified without choices. AC is inherited through [A4]; negative and zero lower bounds are allowed without taking a square root of q_A itself. The zero Hilbert space was handled in step 1.1.

A4step 1.1step 2.1step 3.1step 3.2step 3.3step 4.1

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