Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Splitting stationary sets of fixed smaller cofinality

Statement

In ZFC, if κ is regular uncountable, λ<κ is infinite regular, and SEλκ is stationary, then S has a partition into κ stationary sets.

Facts & Assumptions

[F1]

Cofinality strata, trace, and reflection: Every point of the stratum has cofinality lambda.

[F2]

Intersections of fewer than the cofinality many clubs: Fewer than kappa clubs intersect to a club on regular uncountable kappa.

[F3]

Unboundedly many stationary fibres yield a partition: A regressive function with stationary tail domains at every threshold yields the required partition.

Proof

Given: The objects and hypotheses in the statement.

1.1

Use AC to choose for each αS an increasing cofinal sequence cα:λα. Suppose every coordinate ξ<λ has a threshold bξ<κ for which {αS:cα(ξ)bξ} is nonstationary; choose an avoiding club Cξ.

F1
2.1

The intersection C=ξ<λCξ is club, and b=supξ<λbξ<κ by regularity. Take αSC above b (the intersection is unbounded, by testing it against additional tails). Then cα(ξ)<bξb for every ξ, contradicting cofinality in α>b.

F2step 1.1
3.1

Therefore some fixed coordinate ξ has stationary tail domains at every threshold. The map g(α)=cα(ξ) is regressive on all S. The fibre-partition lemma applies.

F3step 2.1

Depends on

Used by

Dependency tree · two levels

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Sources