Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-03
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The stabilizer GxG_x is a subgroup of GG

Statement

For every left action of a group GG on a set XX and every xXx\in X, the stabilizer GxG_x is a subgroup of GG.

Facts & Assumptions

Given: A left action of GG on XX and xXx\in X.

[L1]

Gx={gG:gx=x}G_x=\{g\in G:g\cdot x=x\} (The orbit GxG\cdot x and stabilizer GxG_x of a point in a group action).

[L2]

The action satisfies ex=xe\cdot x=x and (gh)x=g(hx)(gh)\cdot x=g\cdot(h\cdot x) (Left group actions, transitive actions, and faithful actions).

Proof

technique · direct
1.1

The identity lies in GxG_x, since ex=xe\cdot x=x. Thus GxG_x is nonempty.

L1L2given
1.2

If a,bGxa,b\in G_x, then (ab1)x=a(b1x)=ax=x(ab^{-1})\cdot x=a\cdot(b^{-1}\cdot x)=a\cdot x=x: indeed bx=xb\cdot x=x implies b1x=b1(bx)=xb^{-1}\cdot x=b^{-1}\cdot(b\cdot x)=x. Therefore ab1Gxab^{-1}\in G_x.

L1L2givenalgebra
2.1

The subgroup criterion now gives GxGG_x\le G.

step 1.1step 1.2L3

Depends on

Used by

Cited to discharge well-definedness by The orbit G· x and stabilizer Gₓ of a point in a group action.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 15 results over 11 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources