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Step functions on one period are dense in L^1 on the torus
Statement
Assume the Axiom of Countable Choice.
Let be integrable on one period. For every there is a step function on such that
Equivalently, one-period step functions are dense in .
Facts & Assumptions
Given: The Axiom of Countable Choice, a one-period integrable function , and a real .
The torus conventions identify one-period integrable functions with the objects used on this page (Period-one Fourier coefficients, partial sums, and convolution on the torus).
Assuming the Axiom of Countable Choice, finite linear combinations of interval indicators are dense in (Finite linear combinations of box indicators are dense in for ).
Proof
Define by for and otherwise. Then . By [L2], choose a finite linear combination of interval indicators with
Restrict to and call the restriction . Intersecting each interval in with produces only finitely many subintervals, so is a step function on . Since on ,
Step 2.1 is exactly the claimed density statement on one period.
Depends on
Used by
Dependency tree · two levels
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Sources
- Richard S. Laugesen, Harmonic Analysis Lecture Notes (standard reference, not scraped)
- Loukas Grafakos, Classical Fourier Analysis, 3rd ed. (standard reference, not scraped)