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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
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Finite linear combinations of box indicators are dense in Lp(Rn) for 1p<

Statement

Assume the Axiom of Countable Choice.

Let 1p<. Finite linear combinations of indicator functions of boxes are dense in Lp(Rn).

Facts & Assumptions

Given: The Axiom of Countable Choice, 1p<, ε>0, and fLp(Rn).

[L1]

Simple functions with finite-measure support are dense in Lp (Simple functions with finite-measure support are dense in Lp(μ) for 1p<).

[L2]

Every finite-measure measurable set can be approximated in symmetric difference by a finite union of boxes (A finite-measure measurable set in Rn is approximable in measure by a finite union of boxes).

[L3]

Minkowski's inequality is available in Lp (Minkowski's inequality for integrals, including p=).

Proof

technique · direct
1.1

By [L1], choose a simple function [L1, L2, given, choose] s=j=1maj1Ej with each Ej of finite measure and fsp<ε/2. For each j, choose a finite union of boxes Bj with λn(EjBj)<(ε2m(1+j=1maj))p by [L2].

L1L2givenchoose
2.1

Put [L3, step 1.1, algebra] t:=j=1maj1Bj. Then stpj=1maj1Ej1Bjp=j=1majλn(EjBj)1/p<ε/2 by [L3] and the choice of the Bj.

L3step 1.1algebra
3.1

Therefore [step 1.1, step 2.1, algebra] ftpfsp+stp<ε. Since t is a finite linear combination of box indicators, these functions are dense in Lp(Rn).

step 1.1step 2.1algebra

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