Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite linear combinations of box indicators are dense in Lp(Rn) for 1≤p<∞

Statement

Assume the Axiom of Countable Choice.

Let 1≤p<∞. Finite linear combinations of indicator functions of boxes are dense in Lp(Rn).

Facts & Assumptions

Given: The Axiom of Countable Choice, 1≤p<∞, ε>0, and f∈Lp(Rn).

[L1]

Simple functions with finite-measure support are dense in Lp (Simple functions with finite-measure support are dense in Lp(μ) for 1≤p<∞).

[L2]

Every finite-measure measurable set can be approximated in symmetric difference by a finite union of boxes (A finite-measure measurable set in Rn is approximable in measure by a finite union of boxes).

[L3]

Minkowski's inequality is available in Lp (Minkowski's inequality for integrals, including p=∞).

Proof

technique · direct
1.1L1L2givenchoose

By [L1], choose a simple function [L1, L2, given, choose] s=∑j=1maj 1Ej with each Ej of finite measure and ∥f−s∥p<ε/2. For each j, choose a finite union of boxes Bj with λn(Ej△Bj)<(ε2m(1+∑j=1m∣aj∣))p by [L2].

2.1L3step 1.1algebra

Put [L3, step 1.1, algebra] t:=∑j=1maj 1Bj. Then ∥s−t∥p≤∑j=1m∣aj∣ ∥1Ej−1Bj∥p=∑j=1m∣aj∣ λn(Ej△Bj)1/p<ε/2 by [L3] and the choice of the Bj.

3.1step 1.1step 2.1algebra∎

Therefore [step 1.1, step 2.1, algebra] ∥f−t∥p≤∥f−s∥p+∥s−t∥p<ε. Since t is a finite linear combination of box indicators, these functions are dense in Lp(Rn).

Depends on

Used by

Dependency tree · two levels

20 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources