Alphabeta Math
LemmaStatement: Literature-sourcedProof: Literature-sourcedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The support of a cyclic quotient is its vanishing set

Statement

For an ideal I of a commutative ring R,

SuppR(R/I)={p:Ip}.

Facts & Assumptions

Given: A commutative ring R and an ideal IR.

[L1]

A prime ideal p lies in SuppR(R/I) exactly when (R/I)p0 (Support of a module).

[L2]

Localisation commutes with quotients: (R/I)pRp/IRp (Localisation commutes with quotient rings: S1R/S1ISˉ1(R/I)).

[L3]

The local ring Rp has maximal ideal pRp, and the units are exactly the fractions with numerator outside p (Rp is local with unique maximal ideal pRp).

Proof

technique · direct
1.1

Fix a prime ideal p. By [L2], (R/I)p0 exactly when Rp/IRp0.

L1L2
1.2

If Ip, then every generator i/1 of IRp lies in the maximal ideal pRp from [L3], so IRp is proper and the quotient is nonzero.

L3
1.3

If Ip, choose iIp. Then i/1 is a unit in Rp by [L3], and it lies in IRp, so IRp=Rp and the quotient is zero.

L3choose
2.1

By steps 1.1, 1.2, and 1.3, p lies in SuppR(R/I) exactly when Ip.

step 1.1step 1.2step 1.3

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources