Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-5.6-terra)audited 2026-09-04
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Sylvester inertia makes the Morse index intrinsic

Statement

Let f:MR be smooth and let p be a critical point of f. Then the numbers of positive, negative, and zero directions of any chart matrix of Hessp(f) are independent of the chart. Equivalently, the nullity, index, and coindex of p are intrinsic.

Facts & Assumptions

Given: A smooth function f:MR and a critical point p.

[F1]
[F2]

Nullity, index, and coindex are defined from the Hessian as kernel dimension and maximal negative- and positive-definite dimensions (Nondegenerate critical points, nullity, index, and coindex).

[L2]

The inertia counts are exactly the numbers of positive, negative, and zero entries in a diagonal normal form (Positive and negative definiteness, the inertia (p,q,r), rank p+q, and signature pq of a real symmetric bilinear or quadratic form).

Proof

technique · congruence invariance
1.1

By [F1], any two chart matrices of Hessp(f) are congruent real symmetric matrices.

F1given
2.1

Therefore [L1] and [L2] give the same triple (positive,negative,zero) for every chart matrix.

L1L2step 1.1
3.1

For one diagonal normal form, the zero count is the kernel dimension, the negative count is the maximal dimension of a negative-definite subspace, and the positive count is the maximal dimension of a positive-definite subspace, by [F2] and [L2]. Hence nullity, index, and coindex are the same in every chart.

F2L2step 2.1
4.1

Thus the Morse nullity, index, and coindex are intrinsic.

step 2.1step 3.1

Depends on

Used by

Dependency tree · two levels

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