Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-30
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Tangent-bundle chart transitions are smooth with smooth inverses

Statement

If (U,x) and (V,y) are smooth charts on M, then the transition map y~∘x~−1 on x~(π−1(U∩V)) is smooth, and so is its inverse.

Facts & Assumptions

Given: Smooth charts (U,x) and (V,y) with nonempty overlap.

[F1]

The induced tangent-bundle chart records the base coordinate together with the coefficients in the coordinate tangent basis (The induced tangent bundle chart).

[L1]

Tangent bases transform by the Jacobian of the coordinate change (Change-of-coordinate formula for tangent bases).

[L2]

Matrix inversion preserves Ck regularity on the general linear group (Matrix inversion preserves Ck regularity where the determinant is nonzero).

Proof

technique · direct
1.1F1L1given

If v=∑ivi∂xi∣p, then [L1] gives v=∑jwj∂yj∣p with w=J(a)v, where a:=x(p) and J(a)=D(y∘x−1)(a). Hence y~∘x~−1(a,v)=(y∘x−1(a),J(a)v).

2.1step 1.1

The base part y∘x−1 is smooth, the matrix-valued map a↦J(a) is smooth, and matrix-vector multiplication is polynomial in the entries; therefore the transition map is smooth.

3.1L1L2step 1.1∎

Reversing the roles of x and y gives the inverse transition, whose fiber matrix is J(a)−1. The smoothness of this inverse matrix field follows from [L2], so the inverse transition is smooth.

Depends on

Used by

Dependency tree · two levels

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Sources