Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-07
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The pattern of the terminal H5-overlap quotient is {H5,co-E}-free

Statement

In a co-E-free graph, the pattern graph of a terminal pure iterated H5-overlap quotient is {H5,co-E}-free.

Facts & Assumptions

Given: A terminal pure quotient blockade A in a co-E-free graph.

[F1]

A pattern edge means its two nonempty blocks are complete; a pattern nonedge means they are anticomplete (The pattern graph of a pure blockade).

[F2]

Every initial induced H5 lies wholly in one initial overlap class, and quotienting only merges blocks (The H5-overlap blockade and its iterated mixed quotients).

Proof

technique · contradiction
1.1

Suppose the pattern contains an induced H5, and choose one vertex from each of its eleven corresponding nonempty blocks. By [F1], the selected vertices induce H5 in the ambient graph.

F1assume-contra
1.2

If the pattern contains an induced co-E, selecting one vertex from each of its six blocks and using [F1] similarly induces co-E in the ambient graph, contradicting co-E-freeness.

F1choosecontradiction
2.1

The eleven selected vertices lie in distinct terminal blocks. But [F2] says the vertices of every induced H5 must already lie in one initial overlap class and hence in one terminal block, a contradiction.

step 1.1F2contradiction
3.1

Neither forbidden induced graph occurs in the pattern.

step 2.1step 1.2discharge-contradiction

Depends on

Used by

Dependency tree · two levels

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Sources