Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Test function inclusion in schwartz space is continuous

Statement

For n1, the inclusion ι:D(Rn)S(Rn) is continuous and has dense image. This holds in ZF.

Facts & Assumptions

Given: The LF test space D(Rn) and Schwartz space S(Rn).

[F1]

A linear map from D is continuous exactly when every restriction to DK is continuous (Test function lf topology universal property).

[F2]

Schwartz space is defined by the seminorms pαβ and their locally convex topology (Schwartz space and its seminorms, Schwartz topology and convergence).

[F3]

Smooth compactly supported cutoffs approximate every Schwartz function in all Schwartz seminorms (Smooth compact supports are dense in Schwartz space).

Proof

technique · fixed-support estimates and cutoff density
1.1

Fix compact KRn and φDK. Each Schwartz seminorm has the following fixed-support bound.

F2

pαβ(φ)(supxKxα)supxKβφ(x).

The multiplier on the right is finite, including the zero value when K=. Hence every Schwartz seminorm pulls back continuously to DK. [F2]

2.1

Step 1.1 makes every restricted inclusion DKS continuous. The LF universal property therefore makes ι continuous on all of D.

F1step 1.1
3.1

The approximants in [F3] lie in D and converge in the Schwartz topology to the prescribed Schwartz function. Thus the image of ι is dense. This density argument is separate from continuity, and neither uses a choice axiom.

F3

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources