Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

For disjoint nonempty vertex sets, weak c-sparsity says exactly that the edge density is at most c

Statement

Let G be a finite simple graph, let c0, and let X,YV(G) be disjoint nonempty sets. Then (X,Y) is weakly c-sparse if and only if dG(X,Y)c.

Facts & Assumptions

Given: A finite simple graph G, a real c0, and disjoint nonempty sets X,YV(G).

[L1]

Weak c-sparsity means EG(X,Y)cXY (Sparsity of one vertex set to another, and weak sparsity of a pair).

[L2]

The edge density is dG(X,Y)=eG(X,Y)/(XY), where eG(X,Y) counts ordered pairs (x,y)X×Y that form an edge (Edge counts and densities between nonempty vertex sets).

[L3]

Because X and Y are disjoint, each edge between them contributes exactly one such ordered pair, so eG(X,Y)=EG(X,Y) (Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs).

Proof

technique · direct
1.1

By [L3], the inequality of [L1] is the same as eG(X,Y)cXY.

L1L3
2.1

Since X and Y are nonempty, dividing by XY is legitimate, and [L2] turns the inequality of step 1.1 into dG(X,Y)c.

step 1.1L2algebra
3.1

Reversing the same algebra shows the converse implication, so the two conditions are equivalent.

step 2.1

Depends on

Used by

Dependency tree · two levels

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Sources