Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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For disjoint nonempty vertex sets, weak c-sparsity says exactly that the edge density is at most c

Statement

Let G be a finite simple graph, let c≥0, and let X,Y⊆V(G) be disjoint nonempty sets. Then (X,Y) is weakly c-sparse if and only if dG(X,Y)≤c.

Facts & Assumptions

Given: A finite simple graph G, a real c≥0, and disjoint nonempty sets X,Y⊆V(G).

[L1]

Weak c-sparsity means ∣EG(X,Y)∣≤c∣X∣∣Y∣ (Sparsity of one vertex set to another, and weak sparsity of a pair).

[L2]

The edge density is dG(X,Y)=eG(X,Y)/(∣X∣∣Y∣), where eG(X,Y) counts ordered pairs (x,y)∈X×Y that form an edge (Edge counts and densities between nonempty vertex sets).

[L3]

Because X and Y are disjoint, each edge between them contributes exactly one such ordered pair, so eG(X,Y)=∣EG(X,Y)∣ (Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs).

Proof

technique · direct
1.1L1L3

By [L3], the inequality of [L1] is the same as eG(X,Y)≤c∣X∣∣Y∣.

2.1step 1.1L2algebra

Since X and Y are nonempty, dividing by ∣X∣∣Y∣ is legitimate, and [L2] turns the inequality of step 1.1 into dG(X,Y)≤c.

3.1step 2.1∎

Reversing the same algebra shows the converse implication, so the two conditions are equivalent.

Depends on

Used by

Dependency tree · two levels

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Sources