Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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Cayley-graph neighbourhoods are equipotent, and local finiteness is equivalent to finiteness of the symmetrised subset

Statement

Let G be a group, SG, and S±:=(SS1){e}. Left translation gives a bijection between the neighbourhoods of any two vertices of Cay(G,S). The graph is locally finite exactly when S± is finite; in that case it is regular of finite degree S±.

Facts & Assumptions

Given: A group G, a subset SG, and S±=(SS1){e}.

[F1]

The Cayley graph of a group G with respect to a subset S has vertex set G and edge set {{g,gs}:gG, s(SS1){e}} (The Cayley graph of a group with respect to a subset).

[L1]

A graph is locally finite when every vertex has finitely many neighbours (Locally finite graphs and vertex degree without a finiteness hypothesis).

[L2]

The degree of v is degG(v):=NG(v), equivalently the number of edges incident with v. A graph is r-regular when every vertex has degree r; it is cubic when it is 3-regular. (Adjacency, incidence, open and closed neighbourhoods, vertex degree, minimum degree and maximum degree).

[L3]

A set A is finite when An for some nN. (The cardinality A of a finite set).

Proof

technique · direct
1.1

The neighbours of g are the elements gs with s in the symmetrised set minus the identity, and left multiplication by hg1 is a bijection from the neighbours of g to those of h.

F1L2
2.1

Thus one neighbourhood is finite exactly when all are, which occurs exactly when S± is finite. In that case the degree is defined at every vertex and equals S±, so the graph is regular of that finite degree.

F1L1L2L3step 1.1

Depends on

Used by

Dependency tree · two levels

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Sources