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These labels describe origin, not correctness: citations and verification chips remain separate evidence.
A graph is bull-free if and only if its complement is bull-free
Statement
A finite simple graph is bull-free if and only if its complement is bull-free.
Facts & Assumptions
Given: A finite simple graph .
The bull has vertices and edges , , , , and (The bull graph).
In the complement graph, two distinct vertices are adjacent exactly when they are nonadjacent in the original graph (Graph isomorphisms, automorphisms and graph complements).
A graph is bull-free exactly when it has no induced bull (A bull-free graph).
Proof
By [F1] and [F2], the complement of the bull is again a bull: the bijection , , , , sends nonedges of the bull to edges of the bull.
If contains an induced bull on a vertex set , then is the complement of that bull, hence another bull by step 1.1. The same argument with and interchanged proves the converse implication.
Therefore has an induced bull exactly when does, so [F3] gives the equivalence of bull-freeness.
Depends on
Used by
- A split set with both a complete and an anticomplete outside vertex yields a nontrivial module Theorem
- Every basic bull-free graph is 2-narrow Theorem
- Every bull-free graph is 2-narrow Theorem
- Every composite bull-free graph has a nontrivial module Theorem
- For a vertex in a basic bull-free graph, either its neighborhood or its antineighborhood is perfect Theorem
Dependency tree · two levels
6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Maria Chudnovsky and Shmuel Safra, The Erdős-Hajnal conjecture for bull-free graphs, Section 1 (standard reference, not scraped)
- Maria Chudnovsky, The structure of bull-free graphs III: global structure, Section 2.1 (standard reference, not scraped)