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PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-10
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Coordinate formula for riemannian divergence

Statement

In coordinates, divgX=(detG)1/2i=1ni((detG)1/2Xi).

Facts & Assumptions

Given: A smooth vector field X=iXii.

[F1]

Riemannian divergence: The Riemannian divergence is defined in a local orientation by LXvolg=(divgX)volg. Use def-divergence-relative-to-a-volume-form with the local form of def-riemannian-volume-form-on-an-oriented-manifold. On overlaps, changing orientation multiplies the nonvanishing form by a locally constant sign. The Lie derivative multiplies by that same sign, so its scalar quotient is unchanged and glues even on nonorientable manifolds. Equivalently this differentiates the positive density of lem-the-riemannian-volume-density-is-coordinate-independent and divides by it; the equivalence is local in a density frame. At a boundary use local smooth extensions. In dimension zero every vector field, and hence divergence, is zero.

[F2]

Coordinate formula and well-definedness of divergence: If μ=ρdx1dxn with ρ nowhere zero and X=iXii, then divμX=ρ1i=1ni(ρXi). This defines a smooth global function, also at boundary points. In dimension zero X=0 and divergence is zero.

Proof

technique · direct
1.1

Choose the local coordinate orientation. Its volume coefficient is ρ=detG>0, so the volume-form divergence formula gives divgX=ρ1ii(ρXi), which is the asserted formula.

F1F2given
2.1

Reversing the local orientation replaces ρ by ρ and therefore multiplies numerator and denominator by 1, leaving the quotient unchanged. Thus the expression works on all charts, including nonorientable manifolds and boundary charts with local extensions. For n=0 the sum is empty and divergence is zero.

F1F2step 1.1

Source locator

Lee, definition pp.423–424; local volume-divergence coordinate formula from the declared supplier.

Depends on

Used by

Dependency tree · two levels

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Sources