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Riemannian divergence theorem
Statement
Assume countable choice. On an oriented Riemannian manifold with boundary, , a smooth compactly supported vector field satisfies , with outward unit normal and outward-normal-first boundary orientation.
Facts & Assumptions
Given: The stated oriented manifold, vector field, and countable choice.
Coordinate formula for riemannian divergence: In coordinates, .
The riemannian volume form is the unique positive unit top form: The Riemannian volume form is the unique positive unit section of for the specified orientation and normalized exterior metric.
Pullback of a riemannian metric is riemannian exactly for immersions: is Riemannian if and only if is an immersion. In general it is positive semidefinite, with radical at .
The general Stokes theorem: Assume . Let be an oriented smooth -manifold with boundary, , and let . With and the outward-normal-first orientation, An empty boundary contributes zero; in dimension one its integral is a finite signed sum of point values.
Induced boundary orientation: For an oriented manifold with boundary, orient by the outward-normal-first rule: an outward vector first, followed by a positive boundary determinant, is a positive determinant of .
The boundary tangent space is the boundary-tangent hyperplane: For of an dimensional manifold and the inclusion , the differential identifies with the hyperplane of boundary-tangent vectors in .
The gradient is characterized by inner products: The gradient is the unique smooth vector field satisfying for every smooth vector field .
Riemannian metrics induce metrics on dual tensor and exterior bundles: A Riemannian metric induces smooth metrics on dual, tensor and exterior bundles. On decomposable covectors, ; increasing orthonormal wedge monomials have norm one.
The Axiom of Countable Choice (): The Axiom of Countable Choice, written , is the following statement. > For every family of nonempty sets indexed by > there is a function with domain such that > for every . Equivalently, in the vocabulary of def-choice-function: every at most countable family of nonempty sets (def-countable) has a choice function.
Proof
In a boundary chart let be its inward boundary coordinate. The boundary tangent space is . The gradient identity gives , so the nonzero gradient is perpendicular to that hyperplane. Therefore is smooth, unit and outward, since . The orthogonal complement is a line and exactly one of its two unit vectors is outward; hence these local definitions agree. The boundary inclusion is an immersion, so the induced metric is Riemannian.
Write , with tangent to the boundary. The term vanishes because these vectors lie in a hyperplane. On a positive orthonormal boundary basis the form is positive and unit by the outward-first convention and the normalized exterior pairing. Uniqueness of the boundary volume form gives . For , this identity uses the induced signed zero-form: its value is , so the same scalar identity holds.
The form is smooth and supported in the compact support of . In coordinates . Stokes under countable choice therefore gives . Substitute step 2.1 to obtain the claimed formula. Empty boundary contributes zero, a zero field gives zero on both sides, and compact permits every smooth field. In dimension one the oriented boundary integral is the finite signed endpoint sum.
Source locator
Lee, Propositions 15.32–15.33, pp.390–391, Lemma 16.30 and Theorem 16.32, pp.423–424; boundary and choice hypotheses are checked explicitly.
Depends on
- Coordinate formula for riemannian divergence
- The riemannian volume form is the unique positive unit top form
- Pullback of a riemannian metric is riemannian exactly for immersions
- The general Stokes theorem
- Divergence theorem for a volume form
- Induced boundary orientation
- The boundary tangent space is the boundary-tangent hyperplane
- The gradient is characterized by inner products
- Riemannian metrics induce metrics on dual tensor and exterior bundles
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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Sources
- John M. Lee, Introduction to Smooth Manifolds, second edition (standard reference, not scraped)