Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-09-07
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The boundary tangent space is the boundary-tangent hyperplane

Statement

For p∈∂M of an n≥1 dimensional manifold and the inclusion i:∂M↪M, the differential dip identifies Tp∂M with the hyperplane of boundary-tangent vectors in TpM.

Facts & Assumptions

Given: An n-dimensional smooth manifold M with boundary, where n≥1, and a point p∈∂M.

[L1]

The boundary is an embedded smooth (n−1)-manifold with charts obtained by restricting boundary charts to their faces (The boundary of a positive-dimensional manifold is a closed embedded smooth (n-1)-manifold).

[L2]

The full tangent space TpM has the n boundary-chart coordinate derivations as a basis (Tangent and cotangent bundles extend over a boundary).

[L3]

Boundary-tangent vectors are exactly those with zero last coordinate in a boundary chart (Inward, outward, and boundary-tangent vectors).

Proof

technique · direct
1.1givenL1constructalgebra

By [L1], a restricted face chart on ∂M has coordinate vectors ∂1,…,∂n−1. In the corresponding boundary chart on M, the inclusion is i(x1,…,xn−1)=(x1,…,xn−1,0), so dip sends those vectors to the first n−1 ambient coordinate derivations. Hence dip is injective and its image is their span.

2.1givenL2L3step 1.1∎

In the full basis from [L2], the image found in step 1.1 is precisely the last-coordinate-zero hyperplane, which [L3] identifies with the boundary-tangent vectors.

Depends on

Used by

Dependency tree · two levels

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Sources