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The simple socle of a costandard object
Statement
Fix a finite-dimensional complex semisimple Lie algebra , a Cartan subalgebra , and a positive Borel . Write , when , and .
The costandard object has a unique simple submodule, isomorphic to . Its socle, the sum of all simple submodules, is that submodule.
Facts & Assumptions
Given: The setting above and the hypotheses in the statement.
Fix a finite-dimensional complex semisimple Lie algebra , a Cartan subalgebra , and a positive Borel . Write , when , and . Restricted Chevalley duality is an exact contravariant equivalence , with a natural isomorphism . It preserves each weight-space dimension, the formal character, and every simple composition multiplicity. (Restricted duality is exact and involutive on O)
The proper submodule which is the sum of all proper submodules is the unique maximal submodule of . The quotient is simple and is its unique simple quotient. (A Verma module has a unique simple quotient)
Fix a finite-dimensional complex semisimple Lie algebra , a Cartan subalgebra , and a positive Borel . Write , when , and . For , the standard and costandard objects are The Verma module is defined in def-verma-module, and prop-restricted-duality-is-an-exact-involution-on-category-o supplies the duality on . These symbols name the two objects; no projectivity or highest-weight-category axiom is part of this definition. (Standard and costandard objects)
Proof
Let be the unique maximal proper submodule of . Dualize to obtain an injection . Its image is the annihilator of .
If is any simple submodule, duality gives a simple quotient . Its kernel must be by uniqueness of the maximal submodule. Finite-dimensional weightwise biduality says is exactly that kernel annihilator. Hence all simple submodules have the image already constructed, and their sum equals it.
Depends on
Used by
- The regular integral sl2 block Example
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Lecture 8 §3 Corollary 3.13, p.5 (standard reference, not scraped)