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Coupled finite differences have a covariance-controlled variance
Statement
Let and be square-integrable real simulation outputs with any specified joint law, and let . The central-difference estimator satisfies The formula applies in particular when the two outputs use common random numbers as in Coupled finite-difference simulation-gradient estimator. Positive covariance reduces this variance relative to independent outputs with the same marginals; coupling alone does not guarantee positive covariance.
Facts & Assumptions
Given: Square-integrable real outputs on one probability space and a scalar .
Moments, variance, and covariance on a probability space: variance and covariance are the expectations of centered squares and products.
Coupled finite-difference simulation-gradient estimator: the central difference is , with the joint law fixed by the simulation coupling.
Expectations factor over finite products of independent random variables: independent integrable factors have product expectation equal to the product of their expectations.
Proof
By [F3], . Centering gives All terms are square-integrable by the hypotheses.
Squaring step 1.1, taking expectations, and expanding the cross term by [F1]–[F2] yields
For independent outputs, [F4] gives , so [F2] makes their covariance zero. Thus the right side in step 2.1 is no larger than the independent-output variance exactly when the chosen coupling has nonnegative covariance; no such sign is forced by sharing a random input.
Depends on
Used by
Dependency tree · two levels
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Sources
- Michael C. Fu, Stochastic Gradient Estimation, preprint of Handbook of Simulation Optimization, §§3.1 and 3.3.4 (standard reference, not scraped)