Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-04
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Variance and covariance identities for random variables

Statement

Let X,Y be square-integrable real random variables on one probability space. Then Var(X)=E[X2]E[X]2, Cov(X,Y)=E[XY]E[X]E[Y]. Moreover, covariance is symmetric and bilinear on finite linear combinations. On finite full-power-set probability spaces these formulas reduce to the published finite identities.

Facts & Assumptions

Given: Square-integrable real random variables X,Y.

[L1]

Variance and covariance are the expectations of the centered square and centered product (Moments, variance, and covariance on a probability space).

[L2]

Expectation is linear on integrable random variables (Linearity, monotonicity, and the modulus bound for expectation).

[L3]

Finite probability spaces agree with the full-power-set probability-space formalism (Finite probability spaces are exactly finite full-power-set probability spaces).

Proof

technique · direct
1.1

Expanding (XE[X])2 and applying [L2] gives Var(X)=E[X2]2E[X]E[X]+E[X]2=E[X2]E[X]2. Likewise, Cov(X,Y)=E[XY]E[X]E[Y].

L1L2algebra
2.1

The covariance formula in step 1.1 is symmetric in X and Y, so Cov(X,Y)=Cov(Y,X). If U=i<maiXi and V=j<nbjYj are finite linear combinations of square-integrable real random variables, expanding E[UV]E[U]E[V] and using [L2] gives Cov(U,V)=i<mj<naibjCov(Xi,Yj).

step 1.1L2algebra
3.1

On a finite probability space, [L3] identifies the general formulas above with the already-published finite ones, so the finite and general identities agree exactly.

step 1.1step 2.1L3

Depends on

Used by

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Sources