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Gaussian reparameterization gives two gradient estimators

Example

Let Z∼N(0,1), set Xθ=θ+Z, and use payoff H(x)=x. The objective is J(θ)=EXθ=θ. The pathwise estimator is constant 1; the score estimator is Xθ(Xθ−θ), which is unbiased and has variance θ2+2.

Facts & Assumptions

Given: A standard normal Z, the affine representation Xθ=θ+Z, and the identity payoff H(x)=x.

[A1]

The Axiom of Choice: every family of nonempty sets has a choice function; AC is inherited by the normal-law and score interfaces below.

[F1]

Standard normal and normal laws: Z has symmetric density ϕ(z)=(2π)−1/2e−z2/2, and Xθ is the location-shifted normal law N(θ,1). A positive-variance normal law has its location-scale density gives its density pθ(x)=ϕ(x−θ) on R.

[F2]
[F3]

Pathwise and reparameterized simulation-gradient estimators: with the same Z held fixed, the pathwise estimator is ∂θH(Xθ).

[F4]

A dominated pathwise simulation gradient is unbiased: an integrably dominated continuous pathwise derivative is the derivative of the expected payoff and has finite variance under its second-moment hypothesis.

[F5]

Score and Fisher information: on positive density support the score is ∂θlog⁡pθ.

[F6]

The likelihood-ratio score gradient is unbiased on fixed support: under fixed support, dominated density differentiation, and a finite weighted second moment, ∂θEθH=Eθ[HSθ].

[F7]

A positive-variance normal law has its location-scale density: N(0,2) has density (4π)−1/2e−z2/4.

[F8]

Integrating against a density agrees with integrating the product: the integral of a nonnegative measurable function under a law with density pθ is its integral after multiplication by pθ against Lebesgue measure.

[F9]

Change of variables for expectation: if Z2=2Z with Z∼N(0,1), then EZ22=2EZ2.

[F10]

Moments, variance, and covariance on a probability space and Variance and covariance identities for random variables: variance is the centered second moment and equals the second moment minus squared mean.

[F11]

The Axiom of Choice, AC implies DC implies countable choice, The Axiom of Countable Choice (ACω) and A C^1 diffeomorphism satisfies the change-of-variables formula for nonnegative Lebesgue measurable functions: AC implies Countable Choice, and applying change of variables to reflection z↦−z with the even density in [F1] shows that the standard normal law is symmetric.

[F12]

Change of variables for expectation and Linearity, monotonicity, and the modulus bound for expectation: integrable functions of a random variable may be integrated against its law, and expectation is linear.

Verification

1.1givenF1F2F3F4F11F12algebra

From [F2], 2∣Z∣≤1+Z2 makes Z integrable. By [F11], the law is symmetric; [F12] therefore gives EZ=E[−Z]=−EZ, so EZ=0. Linearity in [F12] gives EXθ=θ. The pathwise payoff derivative is 1 by [F3], has envelope M=1 and second moment 1, so [F4] gives the correct derivative J′(θ)=1 and variance zero.

1.2A1F1F5algebra

Differentiating log⁡pθ(x)=−12(x−θ)2−12log⁡(2π) gives Sθ(x)=x−θ. The support is the fixed set R.

1.3A1F1F2F6F7F8F9F11F12algebra

Fix θ0 and restrict η to ∣η−θ0∣<1. With z=x−θ0 and a=η−θ0, (z−a)2≥z2/2−a2, while ∣x∣∣x−η∣≤(∣z∣+∣θ0∣)(∣z∣+1). Hence ∣x ∂ηpη(x)∣≤Cθ0(1+z2)e−z2/4 for a finite constant Cθ0. By [F7]–[F9], the integral of this majorant is a constant times E[1+Z22]<∞ for Z2∼N(0,2). Also 2∣Z∣3≤Z2+Z4 makes Z3 integrable by [F2]; symmetry in [F11] and [F12] gives EZ3=0. Therefore Eθ[Xθ2Sθ(Xθ)2]=E[(θZ+Z2)2]=θ2+3<∞ by [F2], so [F6] applies.

2.1A1F2F6F10step 1.1step 1.3algebra∎

By [F6], the score estimator has mean J′(θ)=1. Its variance is E[(θZ+Z2)2]−1=θ2+3−1=θ2+2, using [F2] and [F10].

Depends on

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