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Linearity, monotonicity, and the modulus bound for expectation

Statement

Let X,Y be integrable real or complex random variables on one probability space.

  1. For scalars a,b, E[aX+bY]=a E[X]+b E[Y].
  2. If X and Y are real-valued and X≤Y almost surely, then E[X]≤E[Y].
  3. ∣E[X]∣≤E[∣X∣].

Facts & Assumptions

Given: Integrable random variables X,Y.

[L1]

Expectation is the Lebesgue integral against the probability measure (Expectation of a nonnegative or integrable random variable).

[L2]

The Lebesgue integral is linear on L1, the nonnegative integral is monotone, and the modulus of an integral is bounded by the integral of the modulus (The Lebesgue integral is linear on L1(μ), Monotonicity and nonnegative homogeneity of the nonnegative integral, The modulus of an integral is bounded by the integral of the modulus).

[L3]

Almost-everywhere equal integrable functions have equal integrals on every measurable event. (Two integrable functions are equal almost everywhere exactly when all of their indefinite integrals agree)

[L4]

The positive part of a measurable real function is measurable. (Closure properties of measurable functions used by the integral)

Proof

technique · direct
1.1L1L2

Rewriting expectation as the integral by [L1], linearity in [L2] gives E[aX+bY]=a E[X]+b E[Y].

1.2L1L2

Applying the integral triangle inequality from [L2] after [L1] gives ∣E[X]∣=∣∫X dP∣≤∫∣X∣ dP=E[∣X∣].

2.1step 1.1L1L2L3L4

If X≤Y almost surely, put D=Y−X, which is integrable by [L2]. Its positive part D+=max⁡{D,0} is measurable by [L4] and integrable because D+≤∣D∣. Since D≥0 almost surely, D+=D almost surely, so [L3] gives ∫D dP=∫D+ dP≥0, where the last inequality concerns a pointwise nonnegative integrand. By [L1] and step 1.1, 0≤E[Y−X]=E[Y]−E[X], so E[X]≤E[Y].

3.1step 1.1step 1.2step 2.1∎

Steps 1.1, 1.2, and 2.1 prove the three assertions.

Depends on

Used by

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