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A PRDS bound for each BH true-null contribution

Statement

Let P=(P1,…,Pm) be p-value random variables in a probability space, let m≥1, q∈(0,1), and fix an index i in a designated true-null set I0. Suppose Pi is valid under this law and the law of P is PRDS on I0 as defined in Positive regression dependence on true-null coordinates (PRDS). Apply BH at level q, and let Ii indicate that i is rejected and R be the total number rejected. Then

E ⁣[IiR∨1]≤qm.

Facts & Assumptions

Given: A finite vector of p-values, a fixed true-null set containing i, q∈(0,1), validity of Pi, and PRDS on that set. The PRDS conditional-law existence convention carries the Axiom of Choice as stated in Positive regression dependence on true-null coordinates (PRDS).

[F1]

Positive regression dependence on true-null coordinates (PRDS): for each i∈I0 and each increasing Borel D⊆[0,1]m, there is a regular conditional-law version Ki(x,D) that is nondecreasing on the support of Pi.

[F2]

Leave-one-coordinate rejection partition for a step-up rule: for ck=kq/m, the events {Ii=1,R=k} are {Pi≤ck}∩{P−i∈Ci,k}; the sets Ci,k partition the remaining-coordinate space, and Di,k:=⋃j≤kCi,j are increasing Borel sets with Di,m the whole space.

[F3]

Null-valid p-values and familywise and false-discovery error rates: validity means P(Pi≤u)≤u for every u∈[0,1] under the corresponding true-null law.

[F4]

Conditional law given a random element: if Ki is a conditional law of P given Pi, then for every Borel event D, P(Pi∈A,P∈D)=∫AKi(x,D) PPi(dx) for Borel A⊆[0,1].

[F5]

The expectation of an indicator is the probability of the event: an event indicator has expectation equal to its probability.

[F6]

Linearity, monotonicity, and the modulus bound for expectation: expectation is linear on finite sums of integrable terms.

[F7]

Expectation of a nonnegative or integrable random variable: expectation of a bounded measurable random variable is its integral under the law.

[F9]

Every nonempty at-most-countable set has a surjection from N (A nonempty set is at most countable iff it is a surjective image of N).

[A1]

The conditional-law version in [F1] has the monotonicity required by PRDS on the support of the marginal law of Pi.

[A2]

The standard-Borel conditional-law existence interface is used under the Axiom of Choice (The Axiom of Choice) as recorded in Positive regression dependence on true-null coordinates (PRDS).

Proof

technique · decompose by the rejection count and use PRDS to fold the conditional event probabilities

Given: m,q,P,I0,i as in the Statement.

1.1F2F5F6F7givenconstruct

Put ck=kq/m, Ak:={Pi≤ck}, and Bi,k:={P−i∈Ci,k}. If P(Ak)>0, set ak:=P(Ak∩Bi,k)/P(Ak); otherwise set ak=0. By [F2], Ii/(R∨1)=∑k=1mk−11Ak∩Bi,k. The terms are bounded and the sum is finite, so [F5]–[F7] give E[Ii/(R∨1)]=∑k=1m(P(Ak)/k)ak; a zero-probability Ak contributes zero by the definition of ak.

1.2F1A1A2F2given

For each k, lift Di,k to D~i,k:={p∈[0,1]m:p−i∈Di,k}. The coordinate-deletion map from [0,1]m to the remaining-coordinate product is measurable: the preimage of each measurable rectangle is a finite intersection of coordinate cylinders, and such rectangles generate the product sigma-algebra. Hence D~i,k is Borel, and it is coordinatewise increasing. Let gk(x):=Ki(x,D~i,k), nondecreasing on the support by [F1] and [A1]; the kernel exists on this standard-Borel interface under [A2].

1.3F1F8F9givenconstruct

Write Si=supp⁡(μi). The family U:={(a,b)∩[0,1]:a,b∈Q, a<b} is a basis for the relative topology on [0,1]. If U is relative open and x∈U, write U=O∩[0,1] with O open in R by [F8]; choose ε>0 with (x−ε,x+ε)⊆O using [F8], then use rational density from [F8] to choose a,b∈Q with x−ε<a<x<b<x+ε. Thus x∈(a,b)∩[0,1]⊆U. Since Q×Q is nonempty and at most countable by [F8], [F9] gives an enumeration ((an,bn))n∈N of it, whose interval images enumerate U; hence the basis is countable. Let En=(an,bn)∩[0,1] if an<bn and μi((an,bn)∩[0,1])=0, and En=∅ otherwise. By the definition of support in Positive regression dependence on true-null coordinates (PRDS), [0,1]∖Si=⋃n∈NEn. Indeed, a point outside the support has a relative open null neighborhood and hence a basis neighborhood contained in it, which occurs in the enumeration; conversely, membership in any such null basis neighborhood excludes support membership. The right-hand side is a countable union of null Borel sets, so [F8] gives μi([0,1]∖Si)=0. Thus Si is Borel and μi(Si)=1.

2.1F1A1F4F2step 1.3givenalgebra

By [F4], whenever P(Ak)>0, P(Ak∩{P−i∈Di,k})P(Ak)=∫[0,ck]gk(x) μi(dx)μi([0,ck]). For fixed k<m, this average is at most the corresponding average over [0,ck+1]. By step 1.3, both averages may be restricted to Si without changing them. Every supported x≤ck is below every supported y∈(ck,ck+1], so gk(x)≤gk(y) by [F1] and [A1]. The larger-cutoff average is a mixture of the first average and the average over the added interval; the latter is at least the first whenever it has positive mass, and if it has zero mass the two averages agree.

2.2F3step 1.1algebra

By [F3], P(Ak)≤ck=kq/m for every k. Substituting into step 1.1 yields E[Ii/(R∨1)]≤(q/m)∑k=1mak.

3.1F2F4step 1.1step 2.1givenalgebra

Let k0 be the first index with P(Ak0)>0, if one exists; then aj=0 for j<k0, and Ci,k0⊆Di,k0 gives ak0≤P(P−i∈Di,k0∣Ak0)≤1 by step 2.1. For k>k0, suppose ∑j<kaj≤P(P−i∈Di,k−1∣Ak−1). Since P(Ak−1)>0 and Ak−1⊆Ak, step 2.1 applied to the nondecreasing gk−1 makes this at most P(P−i∈Di,k−1∣Ak). Also P(Ak)>0, so [F4] gives ak=P(P−i∈Ci,k∣Ak). The disjoint union Di,k=Di,k−1 ∪˙ Ci,k from [F2] then yields ∑j≤kaj≤P(P−i∈Di,k∣Ak), completing the induction.

4.1F2step 2.2step 3.1algebra∎

If k0 exists, step 3.1 at k=m and Di,m equal to the whole space give ∑k=1mak≤1. If no such k0 exists, all P(Ak)=0 and every ak=0, so the same bound holds. Substituting into step 2.2 proves the contribution inequality.

Remarks

The algebraic contribution bound uses only the PRDS monotonicity for the finite family of sets D~i,k. The inherited Axiom of Choice is used to formulate the standard-Borel conditional-law interface; no choice is used in the finite event decomposition or induction.

Depends on

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