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Two integrable functions are equal almost everywhere exactly when all of their indefinite integrals agree
Statement
Let . Then the following are equivalent:
- almost everywhere;
- for every measurable ,
For integrable real or complex , the notation in condition 2 means ; the product is integrable because .
Facts & Assumptions
Given: Integrable functions .
The integral over a null set vanishes for nonnegative integrands (A nonnegative integral over a null set vanishes).
The Lebesgue integral is linear on (The Lebesgue integral is linear on ).
A nonnegative measurable function has integral exactly when it vanishes almost everywhere (A nonnegative measurable function has integral exactly when it vanishes almost everywhere).
Real and imaginary parts of an integrable complex function are integrable (Integrable real and complex functions, and their integrals).
Proof
Assume almost everywhere, with exceptional null set . Then for [L1, L2, L4, given] every measurable , the real and imaginary parts of are supported on , so [L1] and [L2] give hence .
Assume instead that for every measurable [L2, L3, L4, given] . Apply this to the real part on the set and to on . In each case the corresponding nonnegative integral is , so [L3] gives almost everywhere. The same argument for shows almost everywhere. Hence almost everywhere.
Step 1.1 proves and step 1.2 proves .
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Richard F. Bass, Real Analysis for Graduate Students, Proposition 8.2 (standard reference, not scraped)
- Gerald B. Folland, Real Analysis, 2nd ed., Proposition 2.23(b) (standard reference, not scraped)